我有一个包含三列的SQL查询。我想删除beam_current列中的任何重复值出口。如何这样做。我在sql-server2012中工作
我使用了Distinct但是我也得到了beam_current的重复值。 我的SQL查询是 -
select DISTINCT (beam_current), logtime, beam_energy
from INDUS2_BDS.dbo.DCCT
where logtime between '2014-08-09 01:13:03' and '2014-08-09 02:16:53'
and (beam_current like '%9.96'
or beam_current like '%9.97'
... etc ...)
and beam_energy between '550' and '552'
修改-1 我的输出是 -
在第一栏29.98重复三次。我只想要对应于29.98的行中的任何一行。如何做???
答案 0 :(得分:6)
distinct
关键字适用于整行(所有列),因此:
select DISTINCT (beam_current), logtime, beam_energy
与:
相同select DISTINCT beam_current, logtime, beam_energy
与:
相同select DISTINCT ((beam_current)), (logtime), (((((beam_energy)))))
您可以使用row_number()
仅选择beam_energy
每个值的最新行:
select *
from (
select row_number() over (
partition by beam_current
order by logtime desc) as rn
, *
from INDUS2_BDS.dbo.DCCT
where logtime between '2014-08-09 01:13:03' and '2014-08-09 02:16:53'
and (beam_current like '%9.96'
or beam_current like '%9.97'
... etc ...)
and beam_energy between '550' and '552'
) numbered_rows
where rn = 1 -- Latest row per beam_current
答案 1 :(得分:4)
这将为beam_current的每个值返回1行:
;WITH CTE AS
(
SELECT
row_number() over (partition by beam_current order by (select 1)) rn,
beam_current, logtime, beam_energy
FROM INDUS2_BDS.dbo.DCCT
WHERE
logtime between '2014-08-09 01:13:03' and '2014-08-09 02:16:53'
and (beam_current like '%9.96' or beam_current like '%9.97'
or beam_current like '%9.98' or beam_current like '%9.99'
or beam_current like '%0' or beam_current like '%_0.01'
or beam_current like '%_0.02' or beam_current like '%_0.03'
or beam_current like '%_0.04' or beam_current like '%_0.05'
or beam_current like '%_0.06')
and beam_energy between 550 and 552
)
SELECT beam_current, logtime, beam_energy
FROM CTE
WHERE rn = 1
答案 2 :(得分:2)
对于beam_current的每个值,似乎单行组合是不同的。
如果你只是尝试
select Distinct(beam_current) from INDUS2_BDS.dbo.DCCT where ....
那么只有你才能获得这个独特的价值。
分组也不会起作用,因为它会按照关键字从左到右分组。所以无论如何你都会得到相同的结果。