Question

第一行错误未定义索引：$ pwd 还有未定义的变量。请显示新代码谢谢！它的结尾吐出来了。

$pwd = $_POST['$pwd'];              //Error undefined index: $pwd

if( strlen($pwd) < 8 ) {
        $error .= "Password too short! 
";
}                                     //This line undefined variable

在此处获取错误******错误变量

if( strlen($pwd) > 20 ) {
        $error .= "Password too long! 
";
}

if( strlen($pwd) < 8 ) {
        $error .= "Password too short! 
";
}

if( !preg_match("#[0-9]+#", $pwd) ) {
        $error .= "Password must include at least one number! 
";
}


if( !preg_match("#[a-z]+#", $pwd) ) {
        $error .= "Password must include at least one letter! 
";
}


if( !preg_match("#[A-Z]+#", $pwd) ) {
        $error .= "Password must include at least one CAPS! 
";
}



if( !preg_match("#\W+#", $pwd) ) {
        $error .= "Password must include at least one symbol! 
";
}


if($error){
        echo "Password validation failure(your choice is weak): $error";
} else {
        echo "Your password is strong.";
}

再次感谢：D

Answer 1

而不是$pwd = $_POST['$pwd'];使用$pwd = $_POST['pwd'];

Answer 2

$ pwd = $ _POST ['$ pwd'];

我想这应该是：

$ pwd = $ _POST ['pwd'];

但这取决于密码字段在表单中的名称。如果表单上的密码字段名称是password，则将其设为$ _POST ['password']

Answer 3

如果你有......

<input type="password" name="pwd">

然后在你的php脚本中，你应该调用它

$pwd = $_POST["pwd"];

记下name属性。

PHP未定义的索引/变量

3 个答案: