Question

列名称

优惠券

coupondate

STARTINGDATE

我根据优惠券和开始日期生成优惠券。

FOR EX -

如果优惠券= 500,501且起始日期= 24-02-2015

然后coupondate产生如下..

coupondate = 23-03-2015,23-04-2015

但我需要使用优惠券追加优惠券

FOR EX -

500 - 23-03-2015

501 - 23-04-2015喜欢明智..

plz帮助获得以上输出

下面是我的代码

$coupon = $_POST['coupon'];                         
                    $startingdate = $_POST['startingdate'];                         
                    $coupons = explode(',', $coupon);                       
                    $dates = Array();
                    for ($no = 1; $no < count($coupons) + 1; $no++) 
                    {
                    $dates[] = date("d-m-Y", strtotime($startingdate . " +" . $no . " MONTHS -1 DAYS"));                        
                    }                       
                    $coupondate = implode(',', $dates);

Answer 1

尝试使用foreach而不是for循环，并将优惠券代码与日期一起附加。

$coupon = $_POST['coupon'];
$startingdate = $_POST['startingdate'];
$coupons = explode(',', $coupon);
$dates = Array();
$no = 1;
foreach($coupons as $coupon) {
    $dates[] = $coupon . " - " . date("d-m-Y", strtotime($startingdate . " +" . $no . " MONTHS -1 DAYS"));
    $no++;
}
$coupondate = implode(',', $dates);

echo "<pre>";
print_r($coupondate); //out put you required
echo "</pre>";

php pdo代码用日期追加no

1 个答案: