Question

from PySide.QtCore import *
from PySide.QtGui import *
import time as t


class WorkerThread(QThread):
    def _init_(self, mw):
    super(WorkerThread, self)._init_(mw)
    self.gameName = ""

def setGameName(self, currGameName):
    self.gameName = currGameName

def run(self):
    print self.gameName

class GG(object):
workerThread = WorkerThread()
def startThread(self,stringer):
    self.workerThread.setGameName(stringer)
    self.workerThread.start()

harro = GG()
harro.startThread("hello")
harro.startThread("hi")
t.sleep(60)

这只打印＆＃34; hi＆＃34;而不是＆＃34;你好＆＃34;。为什么不打印？如何更改它以便打印两个？

Answer 1

第二次拨打startThread会取消第一次。线程没有时间打印＆＃34;你好＆＃34;你再次称之为打印＆＃34;嗨＆＃34;。您可以在QThread.wait()之后调用QThread.start()等待线程完成。

一个工作示例（同样，具有正确的标识）：

class WorkerThread(QThread):
    def _init_(self, mw):
        super(WorkerThread, self)._init_(mw)
        self.gameName = ""

    def setGameName(self, currGameName):
        self.gameName = currGameName

    def run(self):
        print self.gameName

class GG(object):
     workerThread = WorkerThread()

     def startThread(self,stringer):
        self.workerThread.setGameName(stringer)
        self.workerThread.start()
        self.workerThread.wait()

harro = GG()
harro.startThread("hello")
harro.startThread("hi")

此示例将在线程运行时冻结用户界面。因此，对于更复杂的任务，您应该使用信号和插槽机制。

Answer 2

这个例子非常小，因为线程只做一件事（打印一个字符串），然后退出。如果你真的想要并行启动两个线程，你可以修改你的GG类来跟踪多个线程对象。

class WorkerThread(QThread):
    def _init_(self, mw):
        super(WorkerThread, self)._init_(mw)
        self.gameName = ""

    def setGameName(self, currGameName):
        self.gameName = currGameName

    def run(self):
        print self.gameName

class GG(object):
     workerThreads = []

     def startThread(self,stringer):
        self.workerThreads.append(WorkerThread())
        self.workerThreads[-1].setGameName(stringer)
        self.workerThreads[-1].start()

harro = GG()
harro.startThread("hello")
harro.startThread("hi")

为什么QThread只打印两个线程调用之一？

2 个答案: