Question

我的范围内有以下数据模型。

        $scope.staff = [
        {"id": "1","name": "Alex"},
        {"id": "2","name": "Brad"},
        {"id": "3","name": "Cam"}
    ];
        $scope.closedShop =[
            {"day": "monday","staffID": "1"},
            {"day": "wednesday","staffID": "2"},
            {"day": "thursday","staffID": "3"},
            {"day": "friday","staffID": "1"}
        ];

我想要做的是输出哪个工作人员每天关闭商店，所以基于上面我的理想输出将是。

亚历克斯星期一关闭了商店

布拉德星期三关闭了商店

Cam周四关闭了商店

亚历克斯星期五关闭了商店

我遇到的问题是closedShop数据只包含staffID，我怎样才能根据staff.id数据来查找这个人名？

我在下面有一个工作示例，但对于少数员工来说，这不是一个可扩展的解决方案吗？

＆＃13;

  'use strict';
    var app = angular.module('app', []);
        app.controller('MainCtrl', ['$scope', function ($scope) {
            $scope.staff = [
            {"id": "1","name": "Alex"},
            {"id": "2","name": "Brad"},
            {"id": "3","name": "Cam"}
        ];
            $scope.closedShop =[
                {"day": "monday","staffID": "1"},
                {"day": "wednesday","staffID": "2"},
                {"day": "thursday","staffID": "3"},
                {"day": "friday","staffID": "1"}
            ];
        }]);

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="app">
    <div ng-controller="MainCtrl">
        <div ng-repeat="closed in closedShop">
            <span ng-if="staff[0].id==closed.staffID">{{staff[0].name}}</span> 
            <span ng-if="staff[1].id==closed.staffID">{{staff[1].name}}</span> 
            <span ng-if="staff[2].id==closed.staffID">{{staff[2].name}}</span> 
            closed the shop on {{closed.day}}
            </div>
    </div>
</div>

＆＃13;

让这项工作最好的方法是什么？

Answer 1

这部分是钱：

<span ng-init="person = (staff | filter:{id:closed.staffID}:true)[0]">{{person.name}}</span>

这可能是不言自明的，但我会详细说明它有所帮助。

您想要显示单个员工的属性，因此我将从{{person.name}}开始。
然后，我们需要获取变量person，因此我们需要使用ng-init来创建变量closed.staffID。
我们需要将工作人员数组过滤为一个成员，因此我们使用＆＃34; strict＆＃34;来过滤( )。参数设置为true，以便我们只获取id匹配的结果。由于过滤语法，此部分需要包含在[0]中。
最后，我们使用person，以便将var app = angular.module('app', []); app.controller('MainCtrl', ['$scope', function ($scope) { $scope.staff = [ {"id": "1","name": "Alex"}, {"id": "2","name": "Brad"}, {"id": "3","name": "Cam"} ]; $scope.closedShop =[ {"day": "monday","staffID": "1"}, {"day": "wednesday","staffID": "2"}, {"day": "thursday","staffID": "3"}, {"day": "friday","staffID": "1"} ]; }]);设置为匹配对象，该对象将是数组中的第一个项目（项目0）。

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="app">
    <div ng-controller="MainCtrl">
        <div ng-repeat="closed in closedShop">
            <span ng-init="person = (staff | filter:{id:closed.staffID}:true)[0]">{{person.name}}</span>
            closed the shop on {{closed.day}}
        </div>
    </div>
</div>

＆＃13;

ng-init="person = getPerson(closed.staffID)"

＆＃13;

您也可以执行app.controller('MainCtrl', ['$scope', 'filterFilter', function ($scope, filter) {并将过滤逻辑移动到控制器中。为此，您将注入过滤器过滤器（有趣的名称），如下所示：

$scope.getPerson = function(id) {
  return filter($scope.staff, {id:id}, true)[0];
};

然后使用此功能：

{{1}}

Answer 2

您可以添加到控制器功能以获取员工ID。

$scope.getStaff = function(id){find and return}

并更改您的观点：

<div ng-app="app">
    <div ng-controller="MainCtrl">
        <div ng-repeat="closed in closedShop">
            <span>{{getStaff(closed.staffID)}}</span> 
            closed the shop on {{closed.day}}
            </div>
    </div>
</div>

Answer 3

可能这不是你所期望的，但是能够正常工作：

HTML：

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="app">
<div ng-controller="MainCtrl">
    <div ng-repeat="closed in closedShop">

        <span ng-repeat="s in staff" ng-if="s.id==closed.staffID">
          {{s.name}}
        </span>
        closed the shop on {{closed.day}}
        </div>
</div>
</div>
<script src="app.js"></script>

<强> JS：

 var app = angular.module('app', []);
    app.controller('MainCtrl', ['$scope', function ($scope) {
        $scope.staff = [
        {"id": "1","name": "Alex"},
        {"id": "2","name": "Brad"},
        {"id": "3","name": "Cam"}
    ];
        $scope.closedShop =[
            {"day": "monday","staffID": "1"},
            {"day": "wednesday","staffID": "2"},
            {"day": "thursday","staffID": "3"},
            {"day": "friday","staffID": "1"}
        ];
    }]);

请参阅此plunkr

使用具有ng-repeat的对象数组中的另一个对象的id属性，通过id查找对象

3 个答案: