在没有在Sparql输出中指定数据类型的情况下打印dateTime

时间:2015-02-24 05:52:39

标签: java rdf sparql jena ontology

我在Jena中使用以下sparql Query来打印一些信息:

   String qr = "PREFIX : <http://www.example.com/tempsensor#>\n" +
               "PREFIX  xsd: <http://www.w3.org/2001/XMLSchema#> \n"+
                 "SELECT \n"+
                "?Place ?Temperature ?Date \n"+ 
                 "WHERE\n"+
                "{ ?ind :locatedIn ?Place .\n " +
                  "?ind :measures ?Temperature .\n " +
                  "?ind :onDate ?Date .\n " +
                "FILTER(regex(str(?Place),'Delhi', 'i'))\n"+
                "FILTER ( datatype(?Date) = xsd:dateTime)\n"+
                "}";

获得的输出是:

 --------------------------------------------------------------
| Place  | Temperature | Date                                |
==============================================================
| :Delhi | 16          | "2014-10-02T03:20:10"^^xsd:dateTime |

但是,我不希望在Date Column中附加数据类型。我需要像

这样的输出
--------------------------------------------------------------
| Place  | Temperature | Date                                |
==============================================================
| :Delhi | 16          | 2014-10-02T03:20:10                 |

我如何在查询中指定此内容?

1 个答案:

答案 0 :(得分:1)

您可以使用项目表达式来获取文字的字符串形式:

String qr = "PREFIX : <http://www.example.com/tempsensor#>\n" +
            "PREFIX  xsd: <http://www.w3.org/2001/XMLSchema#> \n"+
            "SELECT \n"+
            "?Place ?Temperature (STR(?Date) AS ?StrDate) \n"+ 
            "WHERE\n"+
            "{ ?ind :locatedIn ?Place .\n " +
            "  ?ind :measures ?Temperature .\n " +
            "  ?ind :onDate ?Date .\n " +
            "  FILTER(regex(str(?Place),'Delhi', 'i'))\n"+
            "  FILTER ( datatype(?Date) = xsd:dateTime)\n"+
            "}";

在这里,我们使用内置的STR()函数将?Date的值转换为其字符串形式而不使用数据类型。

SPARQL定义了各种内置函数,非常值得您花时间阅读 - http://www.w3.org/TR/sparql11-query/#expressions