Question

我有一个JSON对象数组，其中这些对象也可能是JSON对象的数组。现在，我需要动态地找到一个值，因为no：of对象在数组中不一样。例如，

[
  {
    "Plan": {
      "Node Type": "CTE Scan",
      "CTE Name": "tab",
      "Alias": "tab",
      "Startup Cost": 756.66,
      "Total Cost": 761.16,
      "Plan Rows": 67,
      "Plan Width": 12,
      "Filter": "(sum > 10000)",
      "Plans": [
        {
          "Node Type": "Aggregate",
          "Strategy": "Sorted",
          "Parent Relationship": "InitPlan",
          "Subplan Name": "CTE tab",
          "Startup Cost": 471.70,
          "Total Cost": 756.66,
          "Plan Rows": 200,
          "Plan Width": 8,
          "Plans": [
            {
              "Node Type": "Merge Join",
              "Parent Relationship": "Outer",
              "Join Type": "Inner",
              "Startup Cost": 471.70,
              "Total Cost": 684.82,
              "Plan Rows": 13968,
              "Plan Width": 8,
              "Merge Cond": "(p.pr_id = ep.pr_id)",
              "Plans": [
                {
                  "Node Type": "Sort",
                  "Parent Relationship": "Outer",
                  "Startup Cost": 51.37,
                  "Total Cost": 53.17,
                  "Plan Rows": 720,
                  "Plan Width": 4,
                  "Sort Key": ["p.pr_id"],
                  "Plans": [
                    {
                      "Node Type": "Seq Scan",
                      "Parent Relationship": "Outer",
                      "Relation Name": "product",
                      "Alias": "p",
                      "Startup Cost": 0.00,
                      "Total Cost": 17.20,
                      "Plan Rows": 720,
                      "Plan Width": 4
                    }
                  ]
                },
                {
                  "Node Type": "Sort",
                  "Parent Relationship": "Inner",
                  "Startup Cost": 420.33,
                  "Total Cost": 430.03,
                  "Plan Rows": 3880,
                  "Plan Width": 8,
                  "Sort Key": ["ep.pr_id"],
                  "Plans": [
                    {
                      "Node Type": "Hash Join",
                      "Parent Relationship": "Outer",
                      "Join Type": "Inner",
                      "Startup Cost": 19.00,
                      "Total Cost": 189.05,
                      "Plan Rows": 3880,
                      "Plan Width": 8,
                      "Hash Cond": "(ep.emp_id = e.emp_id)",
                      "Plans": [
                        {
                          "Node Type": "Seq Scan",
                          "Parent Relationship": "Outer",
                          "Relation Name": "employee_vs_product",
                          "Alias": "ep",
                          "Startup Cost": 0.00,
                          "Total Cost": 29.40,
                          "Plan Rows": 1940,
                          "Plan Width": 12
                        },
                        {
                          "Node Type": "Hash",
                          "Parent Relationship": "Inner",
                          "Startup Cost": 14.00,
                          "Total Cost": 14.00,
                          "Plan Rows": 400,
                          "Plan Width": 12,
                          "Plans": [
                            {
                              "Node Type": "Seq Scan",
                              "Parent Relationship": "Outer",
                              "Relation Name": "employee",
                              "Alias": "e",
                              "Startup Cost": 0.00,
                              "Total Cost": 14.00,
                              "Plan Rows": 400,
                              "Plan Width": 12
                            }
                          ]
                        }
                      ]
                    }
                  ]
                }
              ]
            }
          ]
        }
      ]
    }
  }
]

在这里，我需要找到带有“Relaion Name”键的值...这个键有三个值，我们不知道没有：它中存在的对象..所以我需要一个解决方案来查找动态地使用该键的值。

我尝试编写递归函数但我没有成功。如果你知道的话，请帮助我。

我试过的递归函数：

var result1=searchInPlan(jsonarray[0].Plan);
function searchInPlan(node)
{
	var result='';
	{
		if(node.Plans == undefined)
		{
			if(node["Relation Type"] != undefined)
				result +=  node["Relation Name"];
			return result;
		}
		else
		{
			return result+searchInPlans(node.Plans);
		}
	}
}

function searchInPlans(nodes)
{
	console.log("bollo",nodes);
	var result = '';
	for(j=0;j<nodes.length;j++)
	{
		result += searchInPlan(nodes[j]);
	}
	return result;
}

它正在工作，但我只能获得该键的第一个值...我需要使用该键的所有值...帮助我..

Answer 1

这是我的问题的工作代码......

＆＃13;

var x=[];
var y=[];
var i1=0;
var j1=0;
function scan(obj) {
    var k;
    if (obj instanceof Object) {
        for (k in obj) {
            if (obj.hasOwnProperty(k)) {
                if(k == "Relation Name")
				{
					x[i1]= obj[k];
					i1++;
					
				}
                scan(obj[k]);
            }
        }
    }

};

＆＃13;

在jQuery中搜索JSON对象数组中的元素

1 个答案: