Question

我尝试使用assertEquals检查两个列表是否相同，这很好但是当尝试将列表更改为observableList时，测试失败。

那么如何比较JUnit中的两个可观察列表呢？我想仅比较列表的内容。基本上，这些observableLists包含Point对象，而在Point类中，我有hashCodeBuilder和equalsBuilder方法。列表比较需要hashCode()和equals()方法，但我不确定ObservableList是否需要它们。

public class TestClass {
    private MyClass myclass;
    ObservableList<Point> TestPoints = FXCollections.observableArrayList();

    /**
     * @throws java.lang.Exception
     */
    @Before
    public void setUp() throws Exception {
        myclass = new MyClass();

        TestPoints.add(new Point(300.0,200.0));
        TestPoints.add(new Point(600.0,500.0));
        TestPoints.add(new Point(100.0,100.0));
        TestPoints.add(new Point(200.0,200.0));
        TestPoints.add(new Point(100.0,500.0));
        TestPoints.add(new Point(600.0,100.0));
    }

    @Test
    public void testClass() {
        ObservableList<Point> expectedResult = FXCollections.observableArrayList();
        expectedResult.add(new Point(100.0,100.0));
        expectedResult.add(new Point(100.0,500.0));
        expectedResult.add(new Point(600.0,500.0));
        expectedResult.add(new Point(600.0,100.0));

        ObservableList<Point> actualResult = FXCollections.observableArrayList();
        actualResult = myclass.giftWrapping(TestPoints);

        assertEquals(expectedResult, actualResult);
    }

这是点类

public class Point {

    private final DoubleProperty x;
    private final DoubleProperty y;

    public Point() {
        this(0, 0);
    }

    public Point(double x, double y) {
        this.x = new SimpleDoubleProperty(x);
        this.y = new SimpleDoubleProperty(y);
    }
@Override
public int hashCode() {
    HashCodeBuilder hashCodeBuilder = new HashCodeBuilder();
    hashCodeBuilder.append(x);
    hashCodeBuilder.append(y);
    return hashCodeBuilder.toHashCode();
}

@Override
public boolean equals(Object obj) {
    if (this == obj) {
        return true;
    }
    if (obj == null) {
        return false;
    }
    if (!(obj instanceof Point)) {
        return false;
    }
    Point other = (Point) obj;
    EqualsBuilder equalsBuilder = new EqualsBuilder();
    equalsBuilder.append(x, other.x);
    equalsBuilder.append(y, other.y);
    return equalsBuilder.isEquals();
}

如果我使用了List，但是如果我使用了observableList

，那么这将无效

Answer 1

基本上这个问题的问题在于equals和hashCode方法。变量x和变量y必须转换为双精度，因为它们最初是DoubleProperty类型。所以Point类中的equals和hashCode方法应如下所示

@Override
    public int hashCode() {
        HashCodeBuilder hashCodeBuilder = new HashCodeBuilder();
        hashCodeBuilder.append(x.doubleValue());
        hashCodeBuilder.append(y.doubleValue());
        return hashCodeBuilder.toHashCode();
    }

    @Override
    public boolean equals(Object obj) {
        if (this == obj) {
            return true;
        }
        if (obj == null) {
            return false;
        }
        if (!(obj instanceof Point)) {
            return false;
        }
        Point other = (Point) obj;
        EqualsBuilder equalsBuilder = new EqualsBuilder();
        equalsBuilder.append(x.doubleValue(), other.x.doubleValue());
        equalsBuilder.append(y.doubleValue(), other.y.doubleValue());
        return equalsBuilder.isEquals();
    }

这将使测试通过

比较Junit中的两个observable列表

1 个答案: