Question

尝试将多个变量折叠为二分变量。我想使用OR运算符基于条件值在原始变量中分配新值＆＃34; |＆＃34;

数据框c有＆＃34;原因＆＃34;带有值的列：（＆＃34;已回答＆＃34;，＆＃34;无法说话＆＃34;，＆＃34;被叫＆＃34;，＆＃34;未应答＆＃34;，＆＃34;语音邮件＆＃34 ;）

# Collapse several responses into one value
c$answered <- if(c$reason == "answered"  | 
                     "couldNotTalk" |
                     "called_back") 
                    {c$answer == "answered"}
              else {c$unanswer == "not answered"}

这不起作用，但以下是（即使效率不高）：

"Answered" -> c$answer[c$reason == "answered"] 
"Answered" -> c$answer[c$reason == "couldNotTalk"]
"Answered" -> c$answer[c$reason == "called_back"]

Answer 1

在这种情况下，您可以使用%in%而不是做一堆或更多

c$reason %in% c("answered", "couldNotTalk", "called_back")

然后，要使用值向量，而不是使用if，可以使用名为ifelse()的矢量化版本。

c$answered <-  ifelse(
  c$reason %in% c("answered", "couldNotTalk", "called_back"),
  "answered",
  "not answered"
)

或当然你也可以

IfElse with OR运算符

1 个答案: