我需要将XML中的多个字段保存到不同的数组中。 这就是我的XML:
<Content>
<Colours>
<Colour name="Strong Red">
<R>255</R>
<G>0</G>
<B>0</B>
<A>255</A>
</Colour>
</Colours>
<Textures>
<Texture name="Character01">
<Path>Path/Folder</Path>
</Texture>
</Textures>
</Content>
当<Colours>
是我的根,并且我只在一个数组中添加颜色时,一切正常。
现在我想通过同一个XML文件添加Textures以及更多内容,从而将根目录移到<Content>
。
这就是我的ColourLoader类看起来只有Colors而<Colour>
是我的XML的根目录:
[Serializable()]
[XmlRoot("Colours")]
public class ColourLoader
{
[XmlElement("Colour")]
public CustomColour[] Colours;
public static ColourLoader Load(string path)
{
var serializer = new XmlSerializer(typeof(ColourLoader));
using (var stream = new FileStream(path, FileMode.Open))
{
return serializer.Deserialize(stream) as ColourLoader;
}
}
}
我的CustomColour类工作正常,它使用[XmlElement("R")]
等来读取XML中的值。只是因为我不知道如何从嵌套的XML中读取元素。
我不得不跳过<Content>
并以<Colours>
为根添加颜色,并对<Textures>
等执行相同操作。
我不想创建多个XML文件,因为我希望将所有内容管理到一个位置,并且只加载一次XML文件。
答案 0 :(得分:3)
我认为这就是你所追求的。我还提供了一个序列化对象的方法。我发现这对于诊断XML序列化的特殊问题非常有用......
如果这解决了您的问题,请投票给答案。
[Serializable()]
[XmlRoot("Content")]
public class Content
{
[XmlArray("Colours")]
[XmlArrayItem("Colour")]
public CustomColour[] Colours { get; set; }
[XmlArray("Textures")]
[XmlArrayItem("Texture")]
public CustomTexture[] Textures { get; set; }
}
[Serializable()]
[XmlRoot("Colour")]
public class CustomColour
{
[XmlAttribute("name")]
public string Name { get; set; }
[XmlElement("R")]
public int R { get; set; }
[XmlElement("G")]
public int G { get; set; }
[XmlElement("B")]
public int B { get; set; }
[XmlElement("A")]
public int A { get; set; }
}
[Serializable()]
[XmlRoot("Texture")]
public class CustomTexture
{
[XmlAttribute("name")]
public string Name { get; set; }
[XmlElement("Path")]
public string Path { get; set; }
}
public static class ContentLoader
{
public static Content Load(TextReader textReader)
{
var serializer = new XmlSerializer(typeof(Content));
var ret = serializer.Deserialize(textReader) as Content;
return ret;
}
public static void Save(TextWriter textWriter, Content content)
{
var serializer = new XmlSerializer(typeof(Content));
serializer.Serialize(textWriter, content);
}
}
public static void XmlSerializing()
{
var xml = @"<?xml version=""1.0"" encoding=""utf-16""?>
<Content xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"">
<Colours>
<Colour name=""Strong Red"">
<R>255</R>
<G>0</G>
<B>0</B>
<A>255</A>
</Colour>
</Colours>
<Textures>
<Texture name=""Character01"">
<Path>Path/Folder</Path>
</Texture>
</Textures>
</Content>";
var reader = new StringReader(xml);
var content = ContentLoader.Load(reader);
Console.WriteLine("Deserialized version:");
Console.WriteLine(" Colours");
foreach (var colour in content.Colours)
{
Console.WriteLine(" R: {0}, G: {1}, B: {2}, A: {3}", colour.R, colour.G, colour.B, colour.A);
}
Console.WriteLine(" Textures");
foreach (var texture in content.Textures)
{
Console.WriteLine(" Path: {0}", texture.Path);
}
var contentObj = new Content()
{
Colours = new[] { new CustomColour() { Name = "StrongRed", R = 255, G = 0, B = 0, A = 255 } },
Textures = new[] { new CustomTexture() { Name = "Character01", Path = "Path/Folder" } }
};
Console.WriteLine(string.Empty);
Console.WriteLine("Serialized version:");
var writer = new StringWriter();
ContentLoader.Save(writer, contentObj);
Console.WriteLine(writer);
}