Question

我正在使用以下查询来概述我的结果。此时查询显示4个不同的行而不是2.我希望前3列作为查询的键。建议这样做？

select 
    r.ID, m.MATERIALID, m.LOT, ms.AMMOUNT as aantal, 
    m.NETPRICE as prijs, 
    (ms.AMMOUNT * m.NETPRICE) as Total 
from 
    rc_recall r 
inner join 
    RC_RECALLMATSTORE ms on r.ID = ms.RECALLID 
inner join 
    RC_RECALLMATERIAL m ON ms.RECALLID = m.RECALLID and ms.LINE = m.LINE 
where 
    r.ID = '2015073' and d.LANG = 'FR'
group by 
    r.ID, m.MATERIALID m.LOT, ms.AMMOUNT, m.NETPRICE;

我得到的结果：

2015073 | 100654643 | 1 | 2 | 0.9200    | 1.8400000
2015073 | 100654643 | 1 | 5 | 0.9200    | 4.6000000
2015073 | 100654643 | 2 | 3 | 0.9200    | 2.7600000
2015073 | 100654643 | 2 | 5 | 0.9200    | 4.6000000

是否可以使用相同的行计算：'r.ID，m.MATERIALID，m.LOT'彼此？

我想要的结果：

2015073 | 100654643 | 1 | 7 | 0.9200    | 6.4400000
2015073 | 100654643 | 2 | 8 | 0.9200    | 7.3600000

Answer 1

删除＆＃34; ms.AMMOUNT＆＃34;从您的GROUP BY和添加一些SUM（）函数应该做的工作：

select r.ID, m.MATERIALID, m.LOT
        , SUM(ms.AMMOUNT) as aantal
        , m.NETPRICE as prijs
        , SUM(ms.AMMOUNT * m.NETPRICE) as Total
from rc_recall r 
inner join RC_RECALLMATSTORE ms on r.ID = ms.RECALLID 
inner join RC_RECALLMATERIAL m ON ms.RECALLID = m.RECALLID and ms.LINE = m.LINE 
where r.ID = '2015073' and d.LANG = 'FR'
group by r.ID, m.MATERIALID, m.LOT, m.NETPRICE;

Answer 2

如果您不想按AMMOUNT和NETPRICE分组，则必须以其他方式聚合它们，例如MIN或SUM。这将返回您在上面描述的输出，但您需要确认它是否真正正确;

select r.ID, m.MATERIALID, m.LOT, ms.AMMOUNT as aantal, min(m.NETPRICE) as prijs, sum(ms.AMMOUNT * m.NETPRICE) as Total 
from rc_recall r 
inner join RC_RECALLMATSTORE ms on r.ID = ms.RECALLID 
inner join RC_RECALLMATERIAL m ON ms.RECALLID = m.RECALLID and ms.LINE = m.LINE 
where r.ID = '2015073' and d.LANG = 'FR'
group by r.ID, m.MATERIALID m.LOT;

Answer 3

您可能希望使用sum()和其他聚合函数：

select r.ID, m.MATERIALID, m.LOT, sum(ms.AMMOUNT) as aantal,
       sum(m.NETPRICE )as prijs, sum(ms.AMMOUNT * m.NETPRICE) as Total
from rc_recall r inner join
     RC_RECALLMATSTORE ms
     on r.ID = ms.RECALLID inner join
     RC_RECALLMATERIAL m
     ON ms.RECALLID = m.RECALLID and ms.LINE = m.LINE 
where r.ID = '2015073' and d.LANG = 'FR'
group by r.ID, m.MATERIALID, m.LOT;

您还需要将group by修复为正确的粒度。

SQL使用group by计算多行

3 个答案: