我正在使用pjsua的python模块并尝试注册到PBX。
这是代码:
import sys
import pjsua as pj
import threading
def log_cb(level, str, len)
print str,
class MyAccountCallback(pj.AccountCallback)
sem = None
def __init__(self, account)
pj.AccountCallback.__init__(self, account)
def wait(self)
self.sem = threading.Semaphore(0)
self.sem.acquire()
def on_reg_state(self)
if self.sem
if self.account.info().reg_status = 200
self.sem.release()
lib = pj.Lib()
try
lib.init(log_cfg = pj.LogConfig(level=4, callback=log_cb))
lib.create_transport(pj.TransportType.UDP, pj.TransportConfig(5060))
lib.start()
acc = lib.create_account(pj.AccountConfig("181.21.200.109:5060", "561123", "admin"))
acc_cb = MyAccountCallback(acc)
acc.set_callback(acc_cb)
acc_cb.wait()
print n
print Registration complete, status=, acc.info().reg_status,
( + acc.info().reg_reason + )
print nPress ENTER to quit
sys.stdin.readline()
lib.destroy()
lib = None
except pj.Error, e
print Exception + str(e)
lib.destroy()
PBX IP是181.21.200.109 ,我要注册的号码是123456 ,而密码 - 我只是把123(我不是&#39) ;认为PBX需要密码)。
我从PBX获得SIP禁止的SIP数据包(错误的身份验证)。
为了比较,我查看了另一个注册成功的sip客户端的寄存器数据包。 (集团电话发回OPTIONS数据包)。
以下是数据包:
此数据包获取FORBIDEN(错误的身份验证)响应(失败)
REGISTER sip:181.21.200.109:5060 SIP/2.0
Via: SIP/2.0/UDP 181.21.200.50:51117;rport;branch=z9hG4bKPj36c48c6ff87b47ac86c9036e0acbaed4 (Different)
Route: <sip:181.21.200.109:5060;lr> (Different)
Max-Forwards: 70
From: <sip:561123@181.21.200.109>;tag=10a3290c7748480c9c0808366ae0c840 (Different)
To: <sip:561123@181.21.200.109> (Different)
Call-ID: 94f280c9cfcf41539b500ff39582a1ef
CSeq: 21606 REGISTER
User-Agent: pjsip python
Contact: <sip:561123@181.21.200.50:51117;ob> (Different)
Expires: 300
Allow: PRACK, INVITE, ACK, BYE, CANCEL, UPDATE, INFO, SUBSCRIBE, NOTIFY, REFER, MESSAGE, OPTIONS - (Different Options)
Authorization: Digest username="561123", realm="asterisk", nonce="21f4ad6b", uri="sip:181.21.200.109:5060", response="62a339057d2b4e3fed4d368ff94f6d46", algorithm=MD5
Content-Length: 0
此数据包获得OPTIONS响应(成功)
REGISTER sip:181.21.200.109:5060 SIP/2.0
Via: SIP/2.0/UDP 181.21.200.150;rport;branch=z9hG4bK4H5Z6Z2myFUNr
Max-Forwards: 70
From: <sip:561123@181.21.200.109:5060>;tag=307m6Zy8cj7pa
To: <sip:561123@181.21.200.109:5060>
Call-ID: f3ce9234-40e3-1233-a783-5c6b32d1a9b5
CSeq: 3 REGISTER
Contact: <sip:561123@181.21.200.150>
User-Agent: sofia-sip/1.12.11
Allow: REGISTER, INVITE, ACK, BYE, CANCEL, OPTIONS, MESSAGE, SUBSCRIBE, REFER, UPDATE, INFO
Supported: timer, 100rel, path
Authorization: Digest username="561123", realm="asterisk", nonce="7625cf17", algorithm=MD5, uri="sip:181.21.200.109:5060", response="dca3173b2159f812481ca0c96b10a751"
Content-Length: 0
有人知道为什么我会收到禁止的回复吗?我的代码有问题吗?
感谢adcance
答案 0 :(得分:1)
您的PABX 确实需要这些帐户的密码(否则我们不会看到nonce,响应和授权标头本身),因此请确保密码有效。 如果找不到帐户,Asterisk也可以拒绝注册403(配置:alwaysauthreject = yes),并且您的日志没有说明,因为您尝试从python和独立客户端注册不同的扩展名。
最好使用相同的扩展名进行比较(但不要尝试同时注册两个软电话到相同的扩展名)。