我有2个sqlite表:
table1(id INTEGER AUTOINCREMENT,status TEXT,name TEXT);
| id | status | name |
|----|-----------|------|
| 1 | pending | xyz |
| 2 | completed | abc |
table2(状态TEXT,名称TEXT,trans_id INTEGER);
| trans_id | status | name |
|----------|-----------|------|
| 1 | refunded | cvb |
| 2 | cancelled | asd |
我想更新从table2到table1的状态和名称,其中table1.id = table2.trans_id
我有这个问题:
UPDATE table1
SET status = (SELECT t2.status FROM table1 t1,table2 t2 WHERE t1.id = t2.trans_id) ,
name = (SELECT t2.name FROM table1 t1,table2 t2 WHERE t1.id = t2.trans_id)
WHERE id IN (SELECT trans_id FROM table1 t1,table2 t2 WHERE t1.id = t2.trans_id)
它错误地填充了table1。 这是结果table1
| id | status | name |
|----|----------|------|
| 1 | refunded | cvb |
| 2 | refunded | cvb |
我的要求是:
| id | status | name |
|----|-----------|------|
| 1 | refunded | cvb |
| 2 | cancelled | asd |
我的查询有什么问题?我怎样才能实现它?
答案 0 :(得分:8)
我假设t2.trans_id
中的uniq
为primary key
或table2
。如果没有,那么如果它返回多个结果,则更新查询将爆炸。在这种情况下,您需要使用WHERE
应用更多过滤器,或者如果需要任何结果,请使用TOP 1
。
UPDATE table1
SET status = (SELECT t2.status FROM table2 t2 WHERE t2.trans_id = id) ,
name = (SELECT t2.name FROM table2 t2 WHERE t2.trans_id = id)
WHERE id IN (SELECT trans_id FROM table2 t2 WHERE t2.trans_id= id)
答案 1 :(得分:3)
如果table2中有id列,则上一个答案将失败。使用全名table1.id
会更好UPDATE table1
SET status = (SELECT t2.status FROM table2 t2 WHERE t2.trans_id = table1.id) ,
name = (SELECT t2.name FROM table2 t2 WHERE t2.trans_id = table1.id)
WHERE id IN (SELECT trans_id FROM table2 t2 WHERE t2.trans_id= table1.id);