我收到以下错误,但我无法解决此问题。
java.lang.IllegalStateException: No WebApplicationContext found: no ContextLoaderListener registered?
org.springframework.web.context.support.WebApplicationContextUtils.getRequiredWebApplicationContext(WebApplicationContextUtils.java:84)
org.springframework.web.servlet.support.RequestContextUtils.getWebApplicationContext(RequestContextUtils.java:81)
org.springframework.web.servlet.support.RequestContext.initContext(RequestContext.java:219)
org.springframework.web.servlet.support.JspAwareRequestContext.initContext(JspAwareRequestContext.java:74)
org.springframework.web.servlet.support.JspAwareRequestContext.<init>(JspAwareRequestContext.java:48)
org.springframework.web.servlet.tags.RequestContextAwareTag.doStartTag(RequestContextAwareTag.java:76)
org.apache.jsp.student_jsp._jspx_meth_form_005fform_005f0(student_jsp.java:128)
org.apache.jsp.student_jsp._jspService(student_jsp.java:79)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
1.WEB.XML
<servlet>
<servlet-name>jlcindia</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/config/jlcindia-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jlcindia</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
2.jlcindia-servlet.xml中
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://localhost:3306/ankur" />
<property name="username" value="root" />
<property name="password" value="admin" />
</bean>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="annotatedClasses">
<list>
<value>com.vivek.model.Student</value>
</list>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
<prop key="hibernate.hbm2ddl.auto">update</prop>
</props>
</property>
</bean>
<bean id="hibernateTransactionManager"
class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
</bean>
控制器类:
@Controller
public class StudentController {
@Autowired
private StudentService studentService;
public String setupForm(Map <String,Object> map){
System.out.println("setupForm() -> StudentController Called");
Student student=new Student();
map.put("student",student);
map.put("studentList",studentService.getAllstudent());
return "student";
}
@RequestMapping(value="/student.do", method=RequestMethod.POST)
public String doActions(@ModelAttribute Student student,BindingResult result,@RequestParam String actions,Map <String,Object> map){
System.out.println("doActions() -> StudentController Called");
Student studentresult=new Student();
switch (actions.toLowerCase()) {
case "add":
studentService.add(student);
studentresult=student;
case "edit":
studentService.edit(student);
studentresult=student;
case "delete":
studentService.delete(student.getStudentId());
studentresult=new Student();
case "search":
Student searchStudent=studentService.getStudent(student.getStudentId());
studentresult = searchStudent!=null ? searchStudent : new Student();
break;
default:
break;
}
map.put("student",studentresult);
map.put("student",studentService.getAllstudent());
return "student";
}
}
答案 0 :(得分:0)
你可以删除第一个&#34; /&#34;从
<param-value>/WEB-INF/config/jlcindia-servlet.xml</param-value>
为了拥有:
<param-value>WEB-INF/config/jlcindia-servlet.xml</param-value>
答案 1 :(得分:0)
web.xml中使用的标记就是问题。
尝试添加context-param而不是servlet param
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value> </param-value>
</context-param>