Question

好的，我必须用C计算这个税率。基本上，前10,000个不征税，接下来的30,000个税10％，接下来的20,000个税20％。例如：你的收入是60,000。前10,000没有征税，所以现在剩下50,000。其中30,000个中的5万个税率为10％，因此为3,000。你现在有20,000，括号表示下一个20,000的税率是20％，所以4,000。总税收将等于3,000 + 4,000，即7,000。现在我的代码没有提供正确的总数。请注意，这是我在C的第一个学期。

// Aundray Ortiz
// 2/22/15
// COP3223
// tax



int main(){
int income;
int total = 0;

printf("What is your income in dollars?\n");
scanf("%d", &income);

int for_free;
int next_bracket;

for_free = income - 10,0000;
next_bracket = for_free - 30,000;

if (for_free >= 0){
    total = for_free*.1;
}

if (next_bracket >= 0){
    total = total + (next_bracket*.2);

}

printf("You will pay %d in taxes.", total);






return 0;
}

Answer 1

您的代码无效的一个原因是您没有将for_free限制为30000。

另一个问题是10,0000和30,000中存在语法错误（除了错误的值）。您必须删除逗号。

由于使用double进行total = for_free*.1;计算，还有一个编译器警告，当double值写回int时，它可能会截断#include <stdio.h> #define FOR_FREE 10000 #define LOW_BRACKET 30000 #define BIG_BRACKET 20000 #define LOW_RATE 0.10 #define HIGH_RATE 0.20 #define HUGE_RATE 0.50 int main(void) { int income = 0; int lowtaxable = 0, hightaxable = 0, hugetaxable = 0; double taxdue = 0; printf("What is your income in dollars?\n"); scanf("%d", &income); lowtaxable = income - FOR_FREE; if (lowtaxable > LOW_BRACKET) { hightaxable = lowtaxable - LOW_BRACKET; lowtaxable = LOW_BRACKET; } if (hightaxable > BIG_BRACKET) { hugetaxable = hightaxable - BIG_BRACKET; hightaxable = BIG_BRACKET; } taxdue = LOW_RATE * lowtaxable + HIGH_RATE * hightaxable + HUGE_RATE * hugetaxable; printf("You will pay %.2f in taxes.\n", taxdue); return 0; }值

这是清理过的代码，包括更高的税率。

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C中的总数不正确

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