Question

我有一个匹配两个对象的方法。如果第一个对象的每个属性与第二个对象的属性匹配，则会发生匹配。我知道在Groovy中我可以遍历一个对象的字段来执行此操作。问题是我得到了一个我无法弄清楚的异常。

在代码中：

方法：private match(Project projectToMatch, Project project)

项目类：

class Project 
{
    final String name
    final Person techLead
}

我想做类似的事情：

private boolean match(Project projectManaged, Project project) {
    project.properties.each { prop, value ->
        if(value != projectManaged["$prop"] {
            return false
        }
    }
    return true
}

但我得到了：

java.lang.AssertionError: Closure  com.gustavo.tribal.ProjectManagerImplTest$_testEditProjectShouldNotEditIfPriorityAlreadyExists_closure3@32da5a84 
should have failed with an exception of type com.gustavo.tribal.exceptions.WrongProjectException, 
instead got Exception java.lang.NullPointerException: Cannot invoke method call() on null object

两个参数都不为null，但techLead的值适用于两者。我确信null值和异常之间存在关系，但我无法做到。

修改：

测试是：

void testEditProjectShouldNotEditIfPriorityAlreadyExists() {
    projectManagerImpl.addProject(project)
    projectManagerImpl.addProject(project2)
    def msg = shouldFail(WrongProjectException) {
        projectManagerImpl.editProject(project, project2b)
    }
    assertEquals "Can't edit project as the requested priority (" + project2b.priority + ") is already in use", msg
}

editProject的代码：

void editProject(Project project, Project editedProject) {
    for(Project projectManaged : allProjects) {
        if(match(projectManaged, project)) {
            if(projectManaged.priority != editedProject.priority && usedPriorities.get(editedProject.priority)) {
                throw new WrongProjectException("Can't edit project as the requested priority (" + editedProject.priority + ") is already in use")
            }
            removeProject(project)
            addProject(editedProject)
        }
    }
}

Answer 1

事实证明我在match方法中缺少一个括号。另外，我应该使用projectManaged["$prop"]

而不是projectManaged[prop]

查找两个对象是否匹配

1 个答案: