Question

参考此代码： http://learnpythonthehardway.org/book/ex35.html

第12行。

在黄金房间你输入49 python条件不会工作？！（它跳到其他地方）这是python中的一个错误吗？！？！（顺便说一下，我使用的是2.7.8版本）

这是实际情况：

PS C:\Users\Sofia\python_projects> python.exe .\project.py
You are in a dark room.
There is a door to your right and left.
Which one do you take?
> left
There is a bear here.
The bear has a bunch of honey.
The fat bear is in front of another door.
How are you going to move the bear?
> taunt bear
The bear has moved from the door. You can go through it now.
> open door
This room is full of gold.  How much do you take?
> 49
**Man, learn to type a number**. Good job!

而49应该返回：

if how_much < 50:
        print "Nice, you're not greedy, you win!"
        exit(0)

Answer 1

你给我的文章很旧，并且谈论int（）函数。

真正的问题与比较数字无关，而与他如何放置if和else条件的逻辑无关。

这是解决方案：

def gold_room():
    print "This room is full of gold.  How much do you take?"
    choice = raw_input("> ")
    how_much = int(choice)
    if how_much < 50:
    print "Nice, you're not greedy, you win!"
    exit(0)
elif how_much >=50:
    dead("You greedy bastard!")
else:
    dead("Man, learn to type a number.")

对不起伙计们（我只是一个初学者......）但是非常感谢你的帮助！

学习python艰难的练习35 bug找到了

1 个答案: