如何在多个(.txt)文件中输出内容

时间:2015-02-22 07:23:24

标签: c++ loops

我创建了一个程序,它可以从文件中取一个整数作为输入,并生成从1到从文件读取的整数的乘法表。例如,如果程序从文件中读取(3),它将输出:

1*1 = 1
1*2 = 2
... up to
1*10 = 10
and then 
2*1 = 1 
.....
2*10 = 10
and so on up to three suppose that the number read from the file is 3
3*1 = 1
....
3*10 = 30

现在,我试图输出不同(.txt)文件中的每个乘法表,例如table1.txt将包含1*1 = 1 .... up to 1*10 = 10,table2.txt将包含2*1 = 2 .... up to 2*10 = 10和table3的相同过程.TXT。

我只能创建一个只包含第一个乘法表的文件,而且我不知道如何在不同的文件中显示其余的表。

我非常感谢您解决此问题的任何帮助或见解。谢谢!

这就是我所拥有的:

#include <iostream>
#include <fstream>

using namespace std;

int main ()
{
    int num, a, b;
    fstream inputStream;
    ofstream outputStream;

    inputStream.open("input.txt"); //let's say input.txt holds the number 3

    while (inputStream >> num)
    outputStream.open("table.txt");

    for (a = 1; a <= num; a++) 
    {
        for (b = 1; b <= 10; b++)
        {
            outputStream << a << " X "
                   << b << " = "
                   << a*b << endl;
        }
        inputStream.close();
        outputStream.close();
    }                  
    return 0;
}

1 个答案:

答案 0 :(得分:2)

#include <iostream>
#include <string>
#include <fstream>

int main(void) {
    const int Count = 10;              //Count of files
    std::string name = "example_";     //base pattern of file name
    std::ofstream outfstr[Count];      //creating array of 10 output file streams
    for(int i = 0; i < Count; ++i) {   //open all file streams 
        outfstr[i].open(name + char('0' + i) + ".txt");
    }

    for(int i = 0; i < Count; ++i) { // write value of i to i-th stream
         outfstr[i] << "Some rezult " << i;
    }
    return 0;
}