修改 我注意到这是负面的投票，我想这是因为没有展示研究成果。 我看了很多堆栈溢出帖子。我找不到一个JSON这个重度嵌套的例子，这个例子是用JSON中存储的数据后来被操作的例子来访问的。
使用restsharp我收到了对我所做的API调用的JSON响应，但是我正在努力反序列化我得到的响应。我想要使用的数据似乎是一个嵌套数组（下图）。
我的目标是然后将该数组的内容传递给变量，检查它是否已填充，获取该数组的第一项，然后将该项中的属性设置为等于我数据库中的对象。
这是我使用当前代码获取的错误消息。看起来我将Hit对象视为错误类型的对象然而，在将我的头撞到墙壁上几个小时后，我不完全确定为什么特别是这对于这个特定的JSON结构不起作用。
var hitresult = JsonConvert.DeserializeObject( response.Content, typeof( List<Hit> ) ) as List<Hit>;
if (hitresult.Any())
{
var address = hitresult.FirstOrDefault();
verified = true;
result = string.Format( "UDPRN: {0}", address.udprn );
location.Street1 = address.line_1;
location.Street2 = address.line_2;
location.City = address.post_town;
location.State = address.county;
location.PostalCode = address.postcode;
“Newtonsoft.Json.JsonSerializationException”类型的例外 发生在Newtonsoft.Json.dll但未在用户代码中处理
其他信息：无法反序列化当前的JSON对象 （例如{“name”：“value”}）进入类型 'System.Collections.Generic.List`1 [org.hopecorby.LocationService.Hit]' 因为该类型需要一个JSON数组（例如[1,2,3]）来反序列化 正确。
要修复此错误，请将JSON更改为JSON数组（例如 [1,2,3]）或更改反序列化类型，使其成为正常的.NET type（例如，不是像整数这样的基本类型，不是集合类型 像数组或List一样，可以从JSON对象反序列化。 JsonObjectAttribute也可以添加到类型中以强制它 从JSON对象反序列化。
路径'结果'，第1行，第10位。
{
"result": {
"total": 2,
"limit": 10,
"page": 0,
"hits": [
{
"dependant_locality": "",
"postcode_type": "L",
"po_box": "",
"post_town": "LONDON",
"delivery_point_suffix": "1A",
"double_dependant_locality": "",
"su_organisation_indicator": " ",
"longitude": -0.127695242183412,
"department_name": "",
"district": "Westminster",
"building_name": "",
"dependant_thoroughfare": "",
"northings": 179951,
"premise": "10",
"postcode_outward": "SW1A",
"postcode_inward": "2AA",
"sub_building_name": "",
"eastings": 530047,
"postcode": "SW1A 2AA",
"country": "England",
"udprn": 23747771,
"line_3": "",
"organisation_name": "Prime Minister & First Lord Of The Treasury",
"ward": "St James's",
"county": "",
"line_1": "Prime Minister & First Lord Of The Treasury",
"building_number": "10",
"thoroughfare": "Downing Street",
"line_2": "10 Downing Street",
"latitude": 51.5035398826274
},
{
"dependant_locality": "",
"postcode_type": "S",
"po_box": "",
"post_town": "LONDON",
"delivery_point_suffix": "1B",
"double_dependant_locality": "",
"su_organisation_indicator": " ",
"longitude": -0.122624730080001,
"department_name": "",
"district": "Camden",
"building_name": "Downing Court",
"dependant_thoroughfare": "",
"northings": 182178,
"premise": "Flat 10, Downing Court",
"postcode_outward": "WC1N",
"postcode_inward": "1LX",
"sub_building_name": "Flat 10",
"eastings": 530342,
"postcode": "WC1N 1LX",
"country": "England",
"udprn": 26245117,
"line_3": "Grenville Street",
"organisation_name": "",
"ward": "Bloomsbury",
"county": "",
"line_1": "Flat 10",
"building_number": " ",
"thoroughfare": "Grenville Street",
"line_2": "Downing Court",
"latitude": 51.5234851731108
}
]
},
"code": 2000,
"message": "Success"
}
public class Hit
{
public string dependant_locality { get; set; }
public string postcode_type { get; set; }
public string po_box { get; set; }
public string post_town { get; set; }
public string delivery_point_suffix { get; set; }
public string double_dependant_locality { get; set; }
public string su_organisation_indicator { get; set; }
public double longitude { get; set; }
public string department_name { get; set; }
public string district { get; set; }
public string building_name { get; set; }
public string dependant_thoroughfare { get; set; }
public int northings { get; set; }
public string premise { get; set; }
public string postcode_outward { get; set; }
public string postcode_inward { get; set; }
public string sub_building_name { get; set; }
public int eastings { get; set; }
public string postcode { get; set; }
public string country { get; set; }
public int udprn { get; set; }
public string line_3 { get; set; }
public string organisation_name { get; set; }
public string ward { get; set; }
public string county { get; set; }
public string line_1 { get; set; }
public string building_number { get; set; }
public string thoroughfare { get; set; }
public string line_2 { get; set; }
public double latitude { get; set; }
}
public class Result
{
public int total { get; set; }
public int limit { get; set; }
public int page { get; set; }
public List<Hit> hits { get; set; }
}
public class RootObject
{
public Result result { get; set; }
public int code { get; set; }
public string message { get; set; }
}
答案 0 :(得分：3)
Deserializer需要一个JSON数组。您的JSON是包含JSON数组的JSON对象。解串器无法知道您希望它开始使用hits数组。
您需要反序列化为RootObject。然后，您就可以将List<Hit>称为结果的属性。
<强>更新
以下代码应该让您了解我的意思。我测试了这个，它适用于我，你的对象和你的JSON。
var sr = new StreamReader(@"C:\Users\danielc\Documents\Visual Studio 2012\Projects\TestJSON\TestJSON\response.json");
string json = sr.ReadToEnd();
sr.Close();
var root = JsonConvert.DeserializeObject<RootObject>(json);
var result = root.result;
var hits = result.hits;
if (hits.Any())
{
var address = hits.FirstOrDefault();
var udprn = string.Format("UDPRN: {0}", address.udprn);
Console.WriteLine(udprn);
}
Console.Read();