Question

这是我的存储过程，它返回一个Customer_GetCustomers_Result类型：

SELECT c.*, a.City AS AddressCity, a.State AS AddressState
FROM Customer c
LEFT OUTER JOIN Address a ON c.AddressId = a.Id

当使用AutoMapper从Customer_GetCustomers_Result映射到Model.Customer（POCO）时，我希望AddressCity和AddressState映射到Customer.Address.City和Customer.Address.State。

我想使用这个命名约定我不需要为我的AutoMapper配置添加任何特殊内容，除了：

CreateMap<Customer_GetCustomers_Result, Model.Customer>();

我愿意做任何事情来从我的存储过程中获取导航属性。有什么想法吗？

Answer 1

您可以使用AfterMap：

Mapper.CreateMap<Customer_GetCustomers_Result, Model.Customer>()
    .AfterMap((s,t) => 
    {
        t.Address = new Address { 
                                    City = s.AddressCity, 
                                    State = s.AddressState
                                };
    });

甚至可以定义第二个映射......

Mapper.CreateMap<Customer_GetCustomers_Result, Address>()
    .ForMember(t => t.City, m => m.MapFrom(s => s.AdressCity))
    .ForMember(t => t.State, m => m.MapFrom(s => s.AdressState))

然后......

Mapper.CreateMap<Customer_GetCustomers_Result, Model.Customer>()
    .AfterMap((s,t) => 
    {
        t.Address = Mapper.Map<Address>(s);
    });

将展平的存储过程值映射到导航属性

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