Spring JSP传递变量

时间:2015-02-21 21:08:27

标签: java spring jsp

我想处理简单的表格。这是来自我的signUp.jsp的表格,我收到了我的数据

<form:form method="POST" commandName="user-entity" action="process.html">
<table>
    <tr>
        <td><form:label path="userName">Name:</form:label></td>
        <td><form:input path="userName" /></td>
    </tr>
    <tr>
        <td><form:label path="label">Age:</form:label></td>
        <td><form:label path="label"/></td>
    </tr>
    <tr>
        <td colspan="2">
            <input type="submit" value="Submit"/>
        </td>
        <td></td>
        <td></td>
    </tr>
</table>  
</form:form>

我的result.jsp

的一部分
<p>User's name is ${user.userName}. The age is ${user.age}.</p>

和UserController.java

    @Controller
    public class UserController {
        @RequestMapping(value = "/signUp")
        public ModelAndView signUpPage() {
            return new ModelAndView("signUp", "user-entity", new User());
        }

        @RequestMapping(value = "/process")
        public ModelAndView processUser(@ModelAttribute User user) {
            ModelAndView model = new ModelAndView();
            model.setViewName("result");
            model.addObject("user", user);
            return model;
        }

    }

结果我得到了

User's name is ${user.userName}. The age is ${user.password}. 我不知道为什么。哪里可能是问题?

1 个答案:

答案 0 :(得分:0)

缺少 result.jsp中的<%@ page isELIgnored="false"%>

来自here

的解决方案