Question

我想要完成的是显示正确的结果。我所拥有的是两个不同的表格，orders和orders_products。

我尝试将orders.order_date和orders_products.order_date相互匹配并排除秒数，因为数据库之间存在延迟，而且信息不会显示。

orders_products 示例。

id  user_id user_name quantity product price order_date
19  12  Test    1   Advanced game overlay       20     2015-02-17 19:31:16
20  12  Test    1   Advanced standby overlay    20     2015-02-17 19:31:16
21  12  Test    1   Description images          15     2015-02-17 19:31:16

订单示例。

id user_id user_name user_twitch user_email specific_color specific style webcam_size monitor_resolution faster_delivery order_message order_date user_ip order_status order_paid
4   12  Test    John Doe    Test    Test@hotmail.com    Blue    random information  1024x768    0   ... 2015-02-17 19:31:14 xx.xx.xx.xx 1   0

如果您比较这两个表格之间的order_date，orders.order_date的速度会慢2秒，且信息不会显示。

我试图展示一个＆＃34;你的订单＆＃34;页面，和SUM（）每个订单的总和及其列出的产品。

$sth = $conn->prepare(
    "SELECT DATE_FORMAT(order_date, '%Y %m %d %H:%i') AS date_convert "
    . "FROM users, orders "
    . "WHERE users.user_id = :user_id AND orders.user_id = :user_id"
);
$date = date('Y:m:d H:i', strtotime($result['order_date']));

$sth = $conn->prepare(
    "SELECT SUM(price) AS price_sum "
    . "FROM orders_products "
    . "WHERE user_id = :user_id AND order_date = :order_date"
);
$sth->bindValue(':user_id', $row['user_id'], PDO::PARAM_INT);
$sth->bindValue(':order_date', $date, PDO::PARAM_STR);

Answer 1

只需比较日期部分并忽略时间（并修复日期格式）：

// Use Y-m-d as that is the format MySQL is expecting
$date = date('Y-m-d', strtotime($result['order_date']);
// Use DATE() to only use the date poprtion of the datetime value
$sth = $conn->prepare("SELECT SUM(price) AS price_sum FROM orders_products WHERE user_id = :user_id AND DATE(order_date) = :order_date");
$sth->bindValue(':user_id', $row['user_id'], PDO::PARAM_INT);
$sth->bindValue(':order_date', $date, PDO::PARAM_STR);

匹配两个日期没有秒并显示结果

1 个答案: