在mysql中使用其他表获取随机图像

Question

我有2张桌子

人物和图像

表人

+----+--------+----------+
| id | name   | lastname |
+----+--------+----------+
|  1 | Jhon   | Smith    |
|  2 | George | Mutt     |
|  3 | Peter  | Law      |
+----+--------+----------+

表格图片

+----+-----------+------------+
| id | id_people | img        |
+----+-----------+------------+
|  1 |         1 | demo04.jpg |
|  2 |         2 | test1.jpg  |
|  3 |         2 | orange.jpg |
|  4 |         2 | flow.png   |
|  5 |         3 | darth.png  |
|  6 |         3 | green.png  |
+----+-----------+------------+

我需要让所有人随机拥有一张图片。

例如，结果很好。

+----------------------------+
1 | Jhon   | Smith | demo04.jpg
2 | George | Mutt  | orange.jpg
3 | Peter  | Law   | green.png
+----------------------------+

或其他结果。

+----------------------------+
1 | Jhon   | Smith | demo04.jpg
2 | George | Mutt  | test1.jpg
3 | Peter  | Law   | darth.png
+----------------------------+



I used this sql query 

SELECT * 
FROM   `people` p 
       INNER JOIN (SELECT * 
                   FROM   images 
                   ORDER  BY Rand() 
                   LIMIT  1)i 
               ON i.id_people = p.id 
WHERE  1 

但只返回一行。

+----+--------+----------+----+-----------+------------+
| id | name   | lastname | id | id_people | img        |
+----+--------+----------+----+-----------+------------+
|  2 | George | Mutt     |  3 |         2 | orange.jpg |
+----+--------+----------+----+-----------+------------+

出现了什么错误？

Answer 1

在这种情况下，使用相关子查询而不是join：

SELECT p.*,
       (select i.img
        from images i
        where i.id_people = p.id 
        order by rand()
        limit 1
       ) as img
FROM   `people` p ;