Java TreeMap中用户定义的类对象

时间:2015-02-21 12:16:47

标签: java collections treemap

我有一个集合(TreeMap),我想从Object im传递中只打印一个值。这是我正在尝试的代码

Student.java

    class Student {
        int rollno;
        String name;
        int age;
        Student(int rollno,String name,int age){
            this.rollno=rollno;
            this.name=name;
            this.age=age;
         }

         public String toString(){//overriding the toString() method
             return rollno+" "+name+" "+age;
         }

     }

StudentTest.java

 import java.util.*;
 import java.io.*;
 class StudentTest{
     public static void main(String args[]){

         Map<String,Student> al=new TreeMap<String,Student>();
         al.put("a1",new Student(101,"Vijay",23));
         al.put("a2",new Student(106,"Ajay",27));
         al.put("a3",new Student(105,"Jai",21));


         Set set = al.entrySet();
         // Get an iterator
         Iterator i = set.iterator();

         // Display elements
         while(i.hasNext()) {
             Map.Entry me = (Map.Entry)i.next();
             System.out.print(me.getKey() + ": ");
             System.out.println(me.getValue());
         }


         System.out.println(al.get("a1"));

         System.out.println(al.size());

         Set<String> keys =al.keySet();
         for(String key : keys)
             {
                 System.out.println(al.get(key));

             }

        Collection entrySet = al.entrySet();
        Iterator<Student> itr = entrySet.iterator();
        System.out.println("+++++++"+entrySet);
        System.out.println("\n\n\n\n\n");
        System.out.println("+++++++"+itr);
        System.out.println("\n\n\n\n\n");
        while(itr.hasNext())
        {
           Student  st = itr.next();
            System.out.println(st.rollno);
        }
    }
}
  1. 我想只打印一个rollno或name或age的值

  2. 此外,我想将名称打印为Vijay,它只是一个名字 集合

  3. 请让我知道我正在尝试的代码获取错误的解决方案。

1 个答案:

答案 0 :(得分:1)

地图的entrySet是一组Map.Entry<KeyType, ValueType> s。

你有这个:

Collection entrySet = al.entrySet();
Iterator<Student> itr = entrySet.iterator();

如果您在第一行中没有使用原始类型,则错误将更加明显。永远不要使用原始类型:

Collection<Student> entrySet = al.entrySet(); // ERROR HERE - Set<Map.Entry<String, Student>> cannot be cast to Collection<Student>
Iterator<Student> itr = entrySet.iterator();

如果要迭代地图中的值,请使用values

Collection<Student> entrySet = al.values();
Iterator<Student> itr = entrySet.iterator();