Question

我试图在python中创建一个列表列表：

[[0, 1, 2], [4, 5, 6], [8, 9, 10], [11, 12]]

但我的功能并未附加最后一个列表([11,12])

a = [a for a in list(range(13))]
print(a)
final_list = []
b =[]
for num in a:
    if len(b) <3:
        b.append(num)
    else:
        b = []

    if len(b) == 3:
        final_list.append(b)

print(final_list)

[[0, 1, 2], [4, 5, 6], [8, 9, 10]]

Answer 1

# You don't need `a` to be a list here, just iterate the `range` object
for num in range(13):
    if len(b) < 3:
        b.append(num)
    else:
        # Add `b` to `final_list` here itself, so that you don't have
        # to check if `b` has 3 elements in it, later in the loop.
        final_list.append(b)

        # Since `b` already has 3 elements, create a new list with one element
        b = [num]

# `b` might have few elements but not exactly 3. So, add it if it is not empty
if len(b) != 0:
    final_list.append(b)

另外，请检查此classic question以了解有关将列表拆分为大小均匀的块的更多信息。

Answer 2

在print(final_list)之前，添加以下行：

if len(b):
    final_list.append(b)

这将包含仅包含2个元素的列表。

填充python中的列表列表

2 个答案: