Question

我有一个函数，它接受一个json对象，其内容可以是任何类型（字典，数组，字符串等），并根据类型修改对象。

在下面的设计示例函数“foo”中，如何修改字典？我收到编译器错误：

error: '@lvalue $T6' is not identical to '(String, String)'

这是函数

func foo (var item: AnyObject)  {
    // ... other logic that handles item of other types ...    

    // here I know for sure that item is of [String:String] type
    (item as? [String:String])?["name"] = "orange"
    // error: '@lvalue $T6' is not identical to '(String, String)'
}

var fruits = ["name": "apple", "color": "red"]
foo(fruits)

Answer 1

即使您使用了暗淡建议的inout，也无法改变它，但您可以克隆AnyObject并更改克隆本身并将其克隆回阵列果实（您还需要包含＆amp;使用inout参数时的前缀：

var fruits:AnyObject = ["name": "apple", "color": "red"]

// var fruits:AnyObject = ["name":2, "color": 3]

func foo (inout fruits: AnyObject)  {
    // ... other logic that handles item of other types ...

    // here I know for sure that item is of [String:Int] type
    if fruits is [String:Int] {
        var copyItem = (fruits as [String:Int])
        copyItem["name"] = 5
        fruits = copyItem as AnyObject
    }
    // here I know for sure that item is of [String:String] type
    if fruits is [String:String] {
        var copyItem = (fruits as [String:String])
        copyItem["name"] = "orange"
        fruits = copyItem as AnyObject
    }
}

foo(&fruits)

fruits  // ["color": "red", "name": "orange"]

swift：修改字典到位

1 个答案: