这是我的代码,但我不断收到“注意:LinkedListAdd.java使用未经检查或不安全的操作。”我正试图尽我所能摆脱它,但似乎没有任何工作。基类编译很好,没有警告,检查似乎来自add all方法。有什么想法吗?
public class LinkedListAdd<E extends Comparable <E> > extends LinkedList<E>
{
public LinkedListAdd()
{
super();
}
public <E extends Comparable<E> > boolean addAll(final int index, final E[] array)
{
if(index < 0 || index > this.size())
throw new IndexOutOfBoundsException("Index out of bounds");
if(array == null)
throw new NullPointerException("Null array");
Node nn = null;
for(int y = array.length - 1; y >= 0; y--)
{
nn = new Node(array[y], null);
if(this.size() == 0)
{
this.head.next = nn;
this.size += 1;
}
else
{
Node cur = this.head.next, prev = null;
for(int x = 0; x < index; x++)
{
prev = cur;
cur = cur.next;
}
if(prev == null)
{
nn.next = cur;
this.head.next = nn;
this.size += 1;
}
else
{
prev.next = nn;
nn.next = cur;
this.size += 1;
}
}
}
if(nn == null)
return false;
return true;
}
}//end class LinkedListSort
这是基类
public class LinkedList<E extends Comparable <E> >
{
protected static class Node<E extends Comparable <E> >
{
public E data;
public Node<E> next;
public Node()
{
this.next = null;
this.data = null;
}// end DVC
public Node(final E data, final Node<E> next)
{
this.next = next;
this.data = data;
}// end EVC
}// end class Node
protected Node <E> head;
protected int size;
public LinkedList()
{
this.head = new Node<>();
this.size = 0;
}
public void clear()
{
this.head = null;
this.size = 0;
}// end clear
public int size(){return this.size;}
public void addFirst(final E data)
{
this.head.next = new Node<>(data, this.head.next);
size ++;
}// end
public String toString()
{
String temp = "List size: " + this.size;
if(this.head.next == null)
return temp += "\nEmpty List";
else
{
temp += "\n";
Node<E> cur = head.next;
while(cur != null)
{
temp += cur.data + " ";
cur = cur.next;
}
return temp;
}// end else
}// end toString
}// end class
答案 0 :(得分:2)
我建议做的一些事情;首先,我在你的头/下一个/大小/数据上添加get / set方法并将这些字段设为私有
关于你的仿制品;
方法签名应该是
public boolean addAll(final int index, final E[] array)
并且您对该方法中节点的声明需要
Node<E> node