Question

您好我是Boost Spirit的新手，我遇到了qi :: symbol对象的问题。

#include <iostream>
#include <vector>

#define BOOST_SPIRIT_DEBUG
#define BOOST_SPIRIT_DEBUG_OUT std::cerr

#include <boost/config/warning_disable.hpp>
#include <boost/fusion/adapted/struct/adapt_struct.hpp>
#include <boost/fusion/include/adapt_struct.hpp>
#include <boost/fusion/include/io.hpp>
#include <boost/spirit/include/phoenix.hpp>
#include <boost/spirit/include/phoenix_core.hpp>
#include <boost/spirit/include/phoenix_object.hpp>
#include <boost/spirit/include/phoenix_operator.hpp>
#include <boost/spirit/include/phoenix_object.hpp> 
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/qi_symbols.hpp>
#include <boost/spirit/include/qi_nonterminal.hpp>
struct Thing
{
    Thing() = default; 

    Thing(std::string s, std::string t)
    :
        one(s),
        two(t)
    {
    }


    std::string one;
    std::string two;
};

BOOST_FUSION_ADAPT_STRUCT(
    Thing,
    (std::string, one)
    (std::string, two)
)

namespace qi = boost::spirit::qi;
namespace phx = boost::phoenix;
namespace ascii = boost::spirit::ascii;

template <typename Iterator>
struct parse_things : qi::grammar<Iterator, Thing(), ascii::space_type>
{
    parse_things() : parse_things::base_type(keyword)
    {
        qi::symbols<char, Thing> keywords;
        keywords.add
            ("One", Thing("ThingOne","ThingTwo"))
            ("Two", Thing("ThingTwo","ThingOne"));

        keyword %= keywords;
        BOOST_SPIRIT_DEBUG_NODE(keyword);
    }

    qi::rule<Iterator, Thing(), ascii::space_type> keyword;
};

int main(int argc, const char *argv[])
{
    Thing t;
    std::string s("One");
    std::string s2("Two");
    parse_things<std::string::const_iterator> parser;

    bool r = qi::phrase_parse(
            std::cbegin(s),
            std::cend(s),
            parser,
            ascii::space,
            t);

    assert(r == true);
    assert(t.one == "ThingOne");
    assert(t.two == "ThingTwo");
    assert(t.two == "ThingOne");
    assert(t.one == "ThingTwo");

    return 0;
}

这在Visual Studio 2014 Update 4上为我编译，但在解析时会引发访问冲突。我做错了什么？

Answer 1

你应该

qi::symbols<char, Thing> keywords;

结构的成员，而不是构造函数中的临时本地。您的解析器将对symbols对象中的trie数据结构进行陈旧引用。

稍微简化的程序，包含更多测试：

<强> Live On Coliru

//#define BOOST_SPIRIT_DEBUG
#define BOOST_SPIRIT_DEBUG_OUT std::cerr

#include <boost/fusion/adapted/struct.hpp>
#include <boost/fusion/include/io.hpp>
#include <boost/spirit/include/phoenix.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/qi_symbols.hpp>
#include <iostream>
#include <vector>

struct Thing
{
    std::string one;
    std::string two;
};

BOOST_FUSION_ADAPT_STRUCT(
    Thing,
    (std::string, one)
    (std::string, two)
)

namespace qi    = boost::spirit::qi;
namespace phx   = boost::phoenix;
namespace ascii = boost::spirit::ascii;

template <typename Iterator>
struct parse_things : qi::grammar<Iterator, Thing(), ascii::space_type>
{
    parse_things() : parse_things::base_type(keyword)
    {
        keywords.add
            ("One", Thing{"ThingOne","ThingTwo"})
            ("Two", Thing{"ThingTwo","ThingOne"});

        keyword %= keywords;
        BOOST_SPIRIT_DEBUG_NODE(keyword);
    }

    qi::symbols<char, Thing> keywords;
    qi::rule<Iterator, Thing(), ascii::space_type> keyword;
};

int main()
{
    const parse_things<std::string::const_iterator> parser;

    for (std::string const s : { "One", "Two", "Three" })
    {
        auto f = begin(s), l = end(s);
        Thing data;

        bool ok = qi::phrase_parse(f,l,parser,ascii::space,data);

        std::cout << s << ": " << std::boolalpha << ok << ", " << boost::fusion::as_vector(data) << '\n';
        if (f != l)
            std::cout << "Remaining unparsed: '" << std::string(f,l) << "'\n";
    }
}

打印

One: true, (ThingOne ThingTwo)
Two: true, (ThingTwo ThingOne)
Three: false, ( )
Remaining unparsed: 'Three'

提升精神符号会引发访问冲突

1 个答案: