我要做的是制作Editext,只包括不以零开头的单词或数字,所以我这样做了
mPatentNameET.setFilters(new InputFilter[] {
new InputFilter() {
public CharSequence filter(CharSequence src, int start,
int end, Spanned dst, int dstart, int dend) {
if(src.equals("")){ // for backspace
return src;
}
if(src.toString().matches("[a-zA-Z ]+") ||
src.toString().matches("^[123456789][0-9]$")){
return src;
}
return "";
}
}
});
但效果不好,我想从EditText接受例如“Test”或“546”,抱歉我的英文不好
答案 0 :(得分:0)
我像这样解决它:)
mPatentNameET.setFilters(new InputFilter[] {
new InputFilter() {
public CharSequence filter(CharSequence src, int start,
int end, Spanned dst, int dstart, int dend) {
if(src.equals("")){ // for backspace
return src;
}
if((mPatentNameET.getText().toString() + src).matches("[a-zA-Z ]+") ||
(mPatentNameET.getText().toString() + src).matches("^[123456789][0-9]*$")){
return src;
}
return "";
}
}
});
答案 1 :(得分:0)
你可以使用TextWatcher。像这样的东西:
mPatentNameET.addTextChangedListener(new TextWatcher(){
@Override
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
// TODO Auto-generated method stub
}
@Override
public void onTextChanged(CharSequence s, int start, int before,
int count) {
String EditTextString= tx.getText().toString();
if(EditTextString.charAt(0).equals("0")){
//TODO return when starting with 0
}
}
@Override
public void afterTextChanged(Editable s) {
// TODO Auto-generated method stub
}
});