PHP无法识别我的模式MVC中的对象

Question

我希望你能帮我解决这个问题：

我尝试在php + HTML5 + css中实现模式MVC。现在，除了模型之外，当我尝试在我的一个Controller中实例化PHP对象时，我遇到了问题。

特别是，我必须打印有关经过身份验证的用户的数据，该数据存储在一个对象$ userObject中，我尝试使用DataBase数据进行实例化。

所以我声明了，我在Null初始化它，然后，我尝试用他的构造函数实例化它。

之后，当我尝试使用它时，PHP告诉我：“在C：\ Users \ 1USER \ Documents \ EasyPHP-DevServer中的非对象上调用成员函数getEmail（）第99行的-14.1VC11 \ data \ localweb \ projects \ ammPHP \ PHP \ Controller \ LoginController.php“

我向您展示有关问题的代码摘录：

 /**the function handle_input rappresent the core of my controller, that popolates the variables of the master.PHP to make a virtual page and to visualize the user's profile.**/

    private function handle_input(&$request, &$session)
    {
        $userObject = null;
        $mysqli = new mysqli(); 


    //login module: it verify the user data and modify the $_SESSION's array
    //It makes also an object of class AuthenticatedUser that full with the database Data about the logged user.

        if(isset($request["userid"]) && isset($request["password"]))
        {   
            if($this->login($request["userid"], $request["password"]))
            {   
                $session["loggedIn"] = true;    

                $mysqli->connect("localhost", "root", "password", "database"); 
                $userid = $request["userid"]; 
                $password = $request["password"];

                $query = "SELECT * FROM loggeduser WHERE (userID = '$userid') AND (passwd = '$password');";

                $result = $mysqli->query($query);
                //errors checking salted

                while($user = $result->fetch_object())
                {
                    $userObject = new AuthenticatedUser($userid, $password, $user -> email, $user -> nome, $user -> cognome, $user -> dataNascita, $user -> città, $user -> CAP, $user -> indirizzo, $user -> cellulare);

                  }

    }//user is logged-in
    else if(isset($request["logout"]))
    {   
        $this->logout();    
    }


    //Master.php dedicated module: It verify that user is logged-in, then initialize 
    //the variables to popolate the master PHP and to make the virtual page of the profile's user.

    if(isset($_SESSION["loggedIn"]) && $_SESSION[ "loggedIn"]) 
    {
        //CONTROLLO SULLE PAGINA RICHIESTE
        if ($request["subpage"] == "profile") 
        {
            $style = "PHP/view/LoggedUserStyle.php";
            $header = "PHP/view/Header.php";
            $loginFormContent = "PHP/view/loggedUserMenu.php";   //modificato col menù per utenti autenticati
            $slideshow = null;
            $userProfile = "PHP/view/userProfile.php";
            **$user = $userObject -> getEmail(); //Here the problem, PHP tells me that $userObject is not an object! :/**
            $payments = null;
            $orders = null;
            $notFoundContent ="PHP/view/content-not-found.php";
            $footer="PHP/view/footer.php"; 
            include("master.php");
        }
        [...]
     }//closing function handle_input