Question

我正在尝试用C创建一个发票程序，但它没有按照我的意图去做。

这是我的代码：

#include <stdio.h>
#include <string.h>


int main()
{
  int choice;
  char item_name[1000][3][20];
  float item_price[1000][3];
  float quantity[1000][3];
  int k;
  int j;


  k=0;
  j=0;
  for (k=0;k<1000;k++)
  {
    printf ("\n");
    printf ("Enter the item name: ");
    scanf ("%s", item_name[k][j]); 
    printf ("\n"); 
    printf ("Enter the item price: ");
    scanf ("%f", &item_price[k][j]);
    printf ("\n");
    printf ("Enter the item quantity: ");
    scanf ("%f", &quantity[k][j]);
    printf ("\n");

    printf ("|        Quantity         |         Item Name        |        Item Price        |");
    printf ("\n");

    for (j=0;j<1000;j++)
    {
      if (quantity[k][j]==0) break;
      printf ("           %.1f", quantity[k][j]);
      printf ("                          %s", item_name[k][j]);
      printf ("                     %.2f", item_price[k][j]);
      printf ("\n\n");
    }

    printf ("   Would you like to enter another item? Enter '1' for yes and '2' for no: ");
    scanf ("%d", &choice);
    printf ("\n");

    if (choice == 2) break;
    if (k>999) break;
  }
  return 0;
}

这是我想要的输出：

Enter item name: Chips
Enter item price: 0.70
Enter item quantity: 3

|        Quantity        |          Item Name        |     Item Price    | 
            3                         Chips                    0.70

Would you like to enter another item? Enter '1' for yes and '2' for no: 1
Enter item name: Drinks
Enter item price: 1.00
Enter item quantity: 3

|        Quantity        |          Item Name        |     Item Price    | 
            3                         Chips                    0.70
            3                         Drinks                   1.00

Would you like to enter another item? Enter '1' for yes and '2' for no: 2

Answer 1

我认为您最好使用链接列表并将所有项目信息放入结构中，如此

typedef struct ItemData
{
  char *name;
  float price;
  float quantity;
} ItemData_t;

但请注意，对于名称，您必须在将字符串存储在那里之前分配一些内存。查看链接列表的工作方式，非常简单，尤其是指针。

Answer 2

不需要[3] 在for k循环中只是参考[k]
在for j循环中只需参考[j]

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main()
{
    int choice;
    char item_name[1000][20];
    float item_price[1000];
    float quantity[1000];
    int k;
    int j;


    k=0;
    j=0;
    for (k=0;k<1000;k++)
    {
        printf ("\n");
        printf ("Enter the item name: ");
        scanf ("%19s", item_name[k]);
        printf ("\n");
        printf ("Enter the item price: ");
        scanf ("%f", &item_price[k]);
        printf ("\n");
        printf ("Enter the item quantity: ");
        scanf ("%f", &quantity[k]);
        printf ("\n");
        printf ("|        Quantity         |         Item Name        |        Item Price        |");
        printf ("\n");
        for (j=0;j<=k;j++)
        {
            printf ("           %.1f", quantity[j]);
            printf ("                          %s", item_name[j]);
            printf ("                     %.2f", item_price[j]);
            printf ("\n\n");
        }
        printf ("   Would you like to enter another item? Enter '1' for yes and '2' for no: ");
        scanf ("%d", &choice);
        printf ("\n");
        if (choice == 2) break;
        if (k>999) break;
    }
    return 0;
}

在c中累积数组

2 个答案: