Question

do
{
    randomNum = (topBorder + lowBorder)/2;

    printf("Your number is: %d?\n",randomNum);
    printf("My number is(larger-l/smaller-s/correct-c): ");

    scanf("%c", &compare);

    printf("\n");
    if (compare == 's') {
        topBorder = randomNum;
    }
    else if (compare == 'l') {
        lowBorder=randomNum;
    }
    else if (compare == 'c') {
        printf("I like that you take my number.\n");
        return 0;
    }
} while (compare = 1);

程序工作正确，但我不知道为什么写双倍时间*您的号码是:(号码）我的号码是（...）：

./pcIsUser

Please, guess number between 1 and 100.
Your number is: 50?

My number is(larger-l/smaller-s/correct-c): l

***Your number is: 75? My number is(larger-l/smaller-s/correct-c):***

Your number is: 75?
My number is(larger-l/smaller-s/correct-c): s

***Your number is: 62?
My number is(larger-l/smaller-s/correct-c):*** 
Your number is: 62?
My number is(larger-l/smaller-s/correct-c): c

I like that you take my number.

Answer 1

问题

while (compare = 1)

它正在为1分配compare。

你需要

while (compare == 1)

并且您永远不会从1获得scanf()，所以也许

while (compare)

也有效，

scanf("%c", &compare);

正在'\n'中的前一个stdin，因此

scanf(" %c", &compare);

会明确地跳过空格并解决问题。

您还应该check scanf()的返回值，以确保在Linux上按 Ctrl + D 发送EOF的人没有意外发生或< Windows上的kbd> Ctrl + Z 。

为什么程序会做双输出？

1 个答案: