Question

我收到错误，我的代码（Oracle）中缺少关键字。我的想法是创建一个as / was视图花费last3,6,12。因此，我想知道jan14花费的最后3个月，过去3个月中包含的月数将是：Oct13，Nov13，Dec14。

使用合并到account_month_tb （选择account_month_tb.acct_id，account_month_tb.month_start_dt，

--rolling spend buckets
sum(spend) over
(partition by account_month_tb.acct_id order by account_month_tb.month_start_dt
range between interval '3' month preceding and preceding month) as spend_last3,

sum(spend) over
(partition by account_month_tb.acct_id order by account_month_tb.month_start_dt
range between interval '6' month preceding and preceding month) as spend_last6,

sum(spend) over
(partition by account_month_tb.acct_id order by account_month_tb.month_start_dt
range between interval '12' month preceding and preceding month) as spend_last12
--mkdn buckets


from account_month_tb

 ) rolling_14
on (account_month_tb.acct_id = rolling_14.acct_id and
account_month_tb.month_start_dt = rolling_14.month_start_dt)
when matched then update set

account_month_tb.spend_last3 = rolling_14.spend_last3,
account_month_tb.spend_last6 = rolling_14.spend_last6,
account_month_tb.spend_last12 = rolling_14.spend_last12
;
commit;

错误消息：

命令行错误：163列：62 错误报告 - SQL错误：ORA-00905：缺少关键字 00905. 00000 - ＆＃34;缺少关键字＆＃34; *原因：
*行动：提交。

Answer 1

在windowing clause内，preceding month并不代表任何内容，也无效。您的意思是interval '1' month preceding。

在CTE中模拟了一些虚拟数据：

with account_month_tb as (
  select 1 as acct_id,
    trunc(sysdate - (16 * level), 'MM') as month_start_dt,
    level as spend
  from dual
  connect by level < 10
)
select account_month_tb.acct_id, account_month_tb.month_start_dt,
  sum(spend) over (partition by account_month_tb.acct_id
    order by account_month_tb.month_start_dt
    range between interval '3' month preceding
      and interval '1' month preceding) as spend_last3
from account_month_tb;

   ACCT_ID MONTH_START_DT SPEND_LAST3
---------- -------------- -----------
         1 01-09-2014                 
         1 01-10-2014               9 
         1 01-10-2014               9 
         1 01-11-2014              24 
         1 01-12-2014              30 
         1 01-12-2014              30 
         1 01-01-2015              30 
         1 01-01-2015              30 
         1 01-02-2015              20

SQL Fiddle包含三个和更多数据。但是你会得到很多重复，这可能不是你想要的。也许是you just need distinct values。

窗口函数 - 日期之间的范围

1 个答案: