Question

//当我调试此代码时，编译器不编译ContactList.java，因此循环进入无限状态

// Contact.java类

rslt = "START";

            ContactList.userid=getIntent().getStringExtra("userID").toString();

            ContactList con = new ContactList();

            con.join();
            con.start();
            //here control do not go to ContactList.java 
            Log.i("JSONObject", rslt);
            while (rslt == "START") {
                try {
                    Thread.sleep(10);
                } catch (Exception ex) {

                    Toast.makeText(getApplicationContext(), "Error Occured Login Again..!!", Toast.LENGTH_LONG).show();
                }
            }

我的ContactList.java是：

public class ContactList extends Thread {

    public WebServices cs;
      public static String userid;


        public void run(){
            try{
                cs=new WebServices();
                String resp=cs.contactlistcall(userid);  **\\webservice method**
                Contact.rslt = resp;


            }catch(Exception ex)
            {

                Contact.rslt=ex.toString();
            }    
        }

}

//这个resp来自我的sql server数据库，通过.net webservice

Answer 1

使用String比较警告，因为String是Object而不是基本类型：

while (rslt == "START")

应该是

while (rslt.equals("START"))

修改

Contact.java

while (con.getRslt().equals("START"))

android无法访问线程类

1 个答案: