如何使用模态中的后退按钮防止历史状态更改

Question

当我点击Android后退按钮时，我的弹出窗口应该关闭。它没有关闭。弹出窗口不应该出现。我必须覆盖android后退按钮操作。

$ionicPopup.show({
    templateUrl: 'templates/time-picker-12-hour.html',
    title: '<strong>12-Hour Format</strong>',
    subTitle: '',
    scope: scope,
    buttons: [{
        text: 'Cancel'
    }, {
        text: 'Set',
        type: 'button-assertive',
        onTap: function (e) {

            scope.loadingContent = true;

            var totalSec = 0;

            if (scope.time.hours != 12) {
                totalSec = (scope.time.hours * 60 * 60) + (scope.time.minutes * 60);
            } else {
                totalSec = scope.time.minutes * 60;
            }

            if (scope.time.meridian === "AM") {
                totalSec += 0;
            } else if (scope.time.meridian === "PM") {
                totalSec += 43200;
            }
            scope.etime = totalSec;
        }
    }]
})

Answer 1

结帐this solution（但不要忘记取消注册您的事件处理程序 - 请参阅the docs for registerBackButtonAction

编辑：为了回答永久性，代码片段来处理android后退按钮： $ionicPlatform.registerBackButtonAction(function () { //close your ionic modal here }, 100);