如何编写一个体面的过程过滤器?

时间:2010-05-19 01:02:59

标签: emacs

我正在构建一个与Emacs通信的程序,我面临的挑战之一就是编写Emacs的进程过滤器功能。它的输入字符串是一系列要评估的s表达式。这是一个示例:

(gimme-append-to-buffer "25 - William Christie dir, Les Arts Florissants - Scene 2. Prelude - Les Arts Florissants\n")
(gimme-append-to-buffer "26 - William Christie dir, Les Arts Florissants - Cybele: 'Je Veux Joindre' - Les Arts Florissants\n")
(gimme-append-to-buffer "27 - William Christie dir, Les Arts Florissants - Scene 3. Cybele: 'Tu T'Etonnes, Melisse' - Les Arts Florissants\n")
(gimme-append-to-buffer "28 - William Christie dir, Les Arts Florissants - Cybele: 'Que Les Plus Doux Zephyrs'. Scene 4. - Les Arts Florissants\n")
(gimme-append-to-buffer "29 - William Christie dir, Les Arts Florissants - Entree Des Nations - Les Arts Florissants\n")
(gimme-append-to-buffer "30 - William Christie dir, Les Arts Florissants - Entree Des Zephyrs - Les Arts Florissants\n")
(gimme-append-to-buffer "31 - William Christie dir, Les Arts Florissants - Choeur Des Nations' 'Que Devant Vous' - Les Arts Florissants\n")
(gimme-append-to-buffer "32 - William Christie dir, Les Arts Florissants - Atys: 'Indigne Que Je Suis' - Les Arts Florissants\n")
(gimme-append-to-buffer "33 - William Christie dir, Les Arts Florissants - Reprise Du Choeur Des Nations : 'Que Devant Nous' - Les Arts Florissants\n")
(gimme-append-to-buffer "34 - William Christie dir, Les Arts Flor*emphasized text*issants - Reprise De L'Air Des Zephyrs - Les Arts Florissants\n")

我遇到的第一个问题是,当函数被调用时,字符串在某种程度上没有完全形成,所以写(mapcar 'eval (format "(%s)" input-string))之类的东西是行不通的。

为了解决第一个问题,我正在使用一个循环。我写的全部功能是:

 (defun eval-all-sexps (s)
   (loop for x = (ignore-errors (read-from-string s))
          then (ignore-errors (read-from-string (substring s position)))
          while x
          summing (or (cdr x) 0) into position
          doing (eval (car x))))

现在出现的第二个问题是函数被调用了两次,输入有点大,首先是有效但部分内容,然后看起来像剩下的数据。

为了解决这个问题,我正在考虑使用垃圾变量来保留循环中剩下的内容,然后将它连接到下一个调用的输入,但我想知道你们是否有任何其他建议如何更优雅地处理这个问题。

谢谢!

2 个答案:

答案 0 :(得分:3)

这就是我在shell模式下所做的事情 我在流程输出中查找特殊的记录结束字符串,以了解输出何时完成。在那之前,我把这些块连接起来。

(defun my-shell-exec-filter (process result)
  (let ((end-of-result (string-match my-shell-end-of-record-string result)))
    (if (and end-of-result
             (numberp end-of-result)
             (> end-of-result 0))
        (setq my-shell-reply 
              (concat my-shell-reply
                      (substring (substring result 0 end-of-result) 0 -1)))

      (progn
        (setq my-shell-reply (concat my-shell-reply result))
        (accept-process-output process my-shell-exec-timeout 5)))))

这不太正确,因为记录结束字符串可以在该过滤器fn的多个调用中分割。所以要正确,它应该首先连接,然后检查匹配。但无论如何你都明白了。

它也会递归,因此,对于非常长的输入,它可能会导致堆栈溢出异常。所以它肯定不像我想的那么干净。

事情已经开始了

      (setq my-shell-reply nil) 
      (set-process-filter proc my-shell-exec-filter)
      (process-send-string proc "whatever...") 
      (if (not (accept-process-output proc my-shell-exec-timeout 100))
          (error "unexpected response."))

      ;; examine my-shell-reply here ... 

答案 1 :(得分:2)

我的最终解决方案是:

(defun eval-all-sexps (s)
  (let ((s (concat gimme-filter-remainder s)))
    (setq gimme-filter-remainder
          (loop for x = (ignore-errors (read-from-string s))
                then (ignore-errors (read-from-string (substring s position)))
                while x
                summing (or (cdr x) 0) into position
                doing (eval (car x))
                finally (return (substring s position))))))