Google js api动态地为每个标记设置不同的标记图像

时间:2015-02-19 23:57:18

标签: javascript google-maps-api-3

我正在使用他跟随js添加谷歌地图,它在foreach循环中从我的数据库中提取我的所有位置,我希望每个标记都有一个不同的图标,它将存储在一个字段中。

让我们说例如我有一个名为filename的字段,它将存储图像路径/名称(icon.jpg)。

我想知道如何调整由August Li编写的这个脚本来做到这一点。

 <script type="text/javascript">
            //Sample code written by August Li
            var icon = new google.maps.MarkerImage("http://maps.google.com/mapfiles/ms/micons/blue.png",
                       new google.maps.Size(32, 32), new google.maps.Point(0, 0),
                       new google.maps.Point(16, 32));
            var center = null;
            var map = null;
            var currentPopup;
            var bounds = new google.maps.LatLngBounds();
            function addMarker(lat, lng, info) {
                var pt = new google.maps.LatLng(lat, lng);
                bounds.extend(pt);
                var marker = new google.maps.Marker({
                    position: pt,
                    icon: icon,
                    map: map
                });
                var popup = new google.maps.InfoWindow({
                    content: info,
                    maxWidth: 300
                });
                google.maps.event.addListener(marker, "click", function() {
                    if (currentPopup != null) {
                        currentPopup.close();
                        currentPopup = null;
                    }
                    popup.open(map, marker);
                    currentPopup = popup;
                });
                google.maps.event.addListener(popup, "closeclick", function() {
                    map.panTo(center);
                    currentPopup = null;
                });
            }           
            function initMap() {
                map = new google.maps.Map(document.getElementById("map"), {
                    center: new google.maps.LatLng(0, 0),
                    zoom: 14,
                    mapTypeId: google.maps.MapTypeId.ROADMAP,
                    mapTypeControl: true,
                    mapTypeControlOptions: {
                        style: google.maps.MapTypeControlStyle.HORIZONTAL_BAR
                    },
                    navigationControl: true,
                    navigationControlOptions: {
                        style: google.maps.NavigationControlStyle.ZOOM_PAN
                    }
                });
<?php

foreach ($dataProvider->models as $model) {
    echo "addMarker({$model->lat}, {$model->lon}, '<b>$model->name</b><br />$model->website');";
}

?>
 center = bounds.getCenter();
     map.fitBounds(bounds);

     }
     </script>

1 个答案:

答案 0 :(得分:2)

您只需要一个类似的功能:

function makeIcon(filename) {
    return new google.maps.MarkerImage(
                   "http://example.com/path/to/icons/" + filename,
                   new google.maps.Size(32, 32), new google.maps.Point(0, 0),
                   new google.maps.Point(16, 32)
               );
}

当然更新了图标文件位置的路径。

然后您需要更新addMarker函数以接受图标参数:

        function addMarker(lat, lng, gicon, info) {
            var pt = new google.maps.LatLng(lat, lng);
            bounds.extend(pt);
            var marker = new google.maps.Marker({
                position: pt,
                icon: gicon,
                map: map
            });
            ...

然后在PHP循环中,您需要单独添加makeIcon()调用。所以,例如,

<?php
foreach ($dataProvider->models as $model) {
    echo "gicon = makeIcon(your filename);";
    echo "addMarker({$model->lat}, {$model->lon}, gicon, '<b>$model->name</b><br />$model->website');";
}
?>

这回复了根据您的文件名获取gIcon对象的代码,然后将其传递给修改后的addMarker。