Question

我已经成功完成了ADDING阶段，但我确实陷入了编辑阶段。此功能将允许管理员通过浏览器更改特定成员的详细信息。有任何想法吗？这是我为ADDING所做的，但没有编辑。

视图

def edit_member(request, member_id):
    context = RequestContext(request)
    members = get_object_or_404(Member, id=member_id)
    form = MemberForm(request.POST or None, instance=member)

    if request.method == 'POST':
        if form.is_valid():
            form.save()
        else:
            form = MemberForm() 

    return render_to_response("templates/MemberUpdate.html",
        {'members': members, 'form':form}, 
    context)

Forms.py

class MemberForm(forms.ModelForm):
    class Meta:
        model = Member

MemberAdd.html

{% for member in members %}
<table>
    <tr>
        <td>{{ member.name}}</td>
    </tr>
</table>
{% endfor %}

<p><h1>Add new members</h1></p>
<table>
<form action="" method="post">
    <tr>
    {% csrf_token %}
    {{ form.as_p }}
</tr>
    <input type="submit" value = "Submit" />
</form>

回溯：

Request Method: GET
Request URL: http://127.0.0.1:8000/

Django Version: 1.7.3
Python Version: 3.2.3
Installed Applications:
('django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'chess',
 'member')
Installed Middleware:
('django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.auth.middleware.SessionAuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware')


Traceback:
File "/home/naveed/my_py3/lib/python3.2/site-packages/django/core/handlers/base.py" in get_response
  98.                 resolver_match = resolver.resolve(request.path_info)
File "/home/naveed/my_py3/lib/python3.2/site-packages/django/core/urlresolvers.py" in resolve
  343.             for pattern in self.url_patterns:
File "/home/naveed/my_py3/lib/python3.2/site-packages/django/core/urlresolvers.py" in url_patterns
  372.         patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
File "/home/naveed/my_py3/lib/python3.2/site-packages/django/core/urlresolvers.py" in urlconf_module
  366.             self._urlconf_module = import_module(self.urlconf_name)
File "/usr/lib/python3.2/importlib/__init__.py" in import_module
  124.     return _bootstrap._gcd_import(name[level:], package, level)
File "/usr/lib/python3.2/importlib/_bootstrap.py" in _gcd_import
  821.                     loader.load_module(name)
File "/usr/lib/python3.2/importlib/_bootstrap.py" in load_module
  436.         return self._load_module(fullname)
File "/usr/lib/python3.2/importlib/_bootstrap.py" in decorated
  141.             return fxn(self, module, *args, **kwargs)
File "/usr/lib/python3.2/importlib/_bootstrap.py" in _load_module
  342.         exec(code_object, module.__dict__)
File "/home/naveed/my_py3/chess/chess/urls.py" in <module>
  3. from member import views
File "/usr/lib/python3.2/importlib/_bootstrap.py" in load_module
  436.         return self._load_module(fullname)
File "/usr/lib/python3.2/importlib/_bootstrap.py" in decorated
  141.             return fxn(self, module, *args, **kwargs)
File "/usr/lib/python3.2/importlib/_bootstrap.py" in _load_module
  330.         code_object = self.get_code(name)
File "/usr/lib/python3.2/importlib/_bootstrap.py" in get_code
  413.                                 dont_inherit=True)

Exception Type: SystemError at /
Exception Value: ../Objects/tupleobject.c:126: bad argument to internal function

Urls.py

url(r'^$', views.index, name='index'),
url(r'profile', views.profile, name='profile'),
url(r'leaderboard', views.leaderboard, name='leaderboard'),
url(r'MemberForm', views.Form, name='MemberForm'),
url(r'MemberUpdate', views.MemberUpdate, name='MemberUpdate'),
url(r'^admin/', include(admin.site.urls)),

Answer 1

你需要从这样的事情开始：

member = Member.objects.get(pk=member_id)

然后

form = MemberForm(request.POST, instance=member)

您的表单将预先填入成员属性。在POST时，将保存更改。

Answer 2

如果您想要编辑特定的Member实例，则需要从数据库中检索实例，然后将其传递给ModelForm：

def edit_member(request, member_id):
    member = get_object_or_404(Member, id=member_id)
    form = MemberForm(request.POST or None, instance=member)

    if request.method == 'POST':
        if form.is_valid():
            form.save()
            # do something else, like redirect to a different view

    return render(request, 'edit_member.html', {'form': form})

如果您想创建新成员：

    def create_member(request):
        form = MemberForm(request.POST or None)

        if request.method == 'POST':
            if form.is_valid():
                form.save()
                # do something else, like redirect to a different view

        return render(request, 'add_member.html', {'form': form})

由于您可以在同一视图中实际完成创建和编辑操作，所以非常啰嗦，但我想展示每个操作中发生的事情。

除非您需要从视图中添加非常具体的内容，否则没有理由手动从已清理的数据中设置模型字段，因为表单已经完成了致电.is_valid()

此外，您还需要正确形成您的网址格式，因为它们需要正确的正则表达式：

url(r'^$', views.index, name='index'),
url(r'^profile/$', views.profile, name='profile'),
url(r'^leaderboard/$', views.leaderboard, name='leaderboard'),
url(r'^MemberForm/$', views.Form, name='MemberForm'),
url(r'^MemberUpdate/(?P<member_id>\d+)/$',
    views.MemberUpdate, name='MemberUpdate'),
url(r'^admin/', include(admin.site.urls))

并请在Python中使用方法，属性和函数的小写名称和类的大写名称。

最后，您需要更新模板代码以传递member_id：

{% for member in members %}
<table>
    <tr>
        <td><a href="{% url 'MemberUpdate' member_id=member.id %}">{{ member.name}}</a></td>
    </tr>
</table>
{% endfor %}

如何通过浏览器更新数据库？ DJANGO

2 个答案: