Question

我正在尝试编写执行以下操作的查询：

从访问表
对于日期范围中的每个日期，搜索遭遇表
生成一个表格，显示每个日期以及谁在其上看到患者日期。
注意：
可能在该日期未见患者应该导致NULL或类似情况
多个医疗服务提供者可能在某个日期看到患者，该日期应该会导致该日期超过一行。

简化示例：
Start_Date：01-JAN-15
End_Date：04-JAN-15

期望的输出：

╔══════╦══════════╦═══════╦═══════╗
║  ID  ║   DATE   ║ NAME  ║ TYPE  ║
╠══════╬══════════╬═══════╬═══════╣
║ 2222 ║ 1-Jan-15 ║ Smith ║ Note  ║
║ 2222 ║ 2-Jan-15 ║ Jones ║ Note  ║
║ 2222 ║ 2-Jan-15 ║ Smith ║ Order ║
║ 2222 ║ 3-Jan-15 ║ NULL  ║       ║
║ 2222 ║ 4-Jan-15 ║ Jones ║ Note  ║
╚══════╩══════════╩═══════╩═══════╝

这是我到目前为止所得到的。这会生成一个列表，列出这些特定提供者何时看到患者但在没有看到患者的情况下不会导致NULL。

SELECT V.VISIT_ID, ET.ENCOUNTER_TRANSACTION_DATE, P.NAME_LAST, ETT.ENC_TRANS_TYPE_NAME
FROM VISIT V
RIGHT OUTER JOIN ENCOUNTER_TRANSACTION ET ON V.VISIT_ID = ET.VISIT_ID AND V.INSTITUTION_ID = ET.INSTITUTION_ID
INNER JOIN ENCOUNTER_TRANSACTION_TYPE ETT ON ET.ENCOUNTER_TYPE_ID = ETT.ENCOUNTER_TRANSACTION_TYPE_ID
INNER JOIN LOCAL_PROVIDER LP ON ET.ORDERING_PROVIDER_ID = LP.LOCAL_PROVIDER_ID
INNER JOIN PERSON_IDENTIFIER I ON I.IDENTIFIER = LP.PROVIDER_NUMBER AND I.IDENTIFIER_SYS_ID = LP.PROVIDER_NUMBER_SYS_ID  
INNER JOIN PERSON P ON P.PERSON_ID = I.PERSON_ID
WHERE
  V.INSTITUTION_ID = 1 AND
  V.END_DATE IS NOT NULL AND
  V.VOIDED_YN = 'N' AND
  V.CARE_SETTING_CODE = 'I' AND
  V.PATIENT_TEAM_ID IN (16, 17, 18) AND
  V.START_DATE >= (TRUNC(ADD_MONTHS(CURRENT_DATE, -1),'mon')) AND
  V.START_DATE <= (LAST_DAY(ADD_MONTHS(CURRENT_DATE, -1))) AND
  I.IDENTIFIER IN (
    '1234', --Smith
    '4321', --Jones
  )
ORDER BY V.VISIT_ID ASC, ET.ENCOUNTER_TRANSACTION_DATE ASC;

当前输出（缺少03-JAN-15的NULL行）：

╔══════╦══════════╦═══════╦═══════╗
║  ID  ║   DATE   ║ NAME  ║ TYPE  ║
╠══════╬══════════╬═══════╬═══════╣
║ 2222 ║ 1-Jan-15 ║ Smith ║ Note  ║
║ 2222 ║ 2-Jan-15 ║ Jones ║ Note  ║
║ 2222 ║ 2-Jan-15 ║ Smith ║ Order ║
║ 2222 ║ 4-Jan-15 ║ Jones ║ Note  ║
╚══════╩══════════╩═══════╩═══════╝

Answer 1

以下是您可以获得一系列日期的方法：

 SELECT DATE'2015-01-01' + LEVEL - 1
   FROM dual
CONNECT BY DATE'2015-01-01' + LEVEL - 1 < DATE'2015-02-01';

以上所有日期均为2015年1月1日至2015年1月31日。

使用上述内容，您可以插入开始日期和结束日期并创建CTE，然后在日期使用外部联接：

WITH dr AS (
    SELECT DATE'2015-01-01' + LEVEL - 1 AS transaction_date
      FROM dual
   CONNECT BY DATE'2015-01-01' + LEVEL - 1 < DATE'2015-01-04'
)
SELECT V.VISIT_ID, dr.transaction_date
     , P.NAME_LAST, ETT.ENC_TRANS_TYPE_NAME
...
       ENCOUNTER_TRANSACTION ET RIGHT JOIN dr
    ON ET.ENCOUNTER_TRANSACTION_DATE = dr.transaction_date

更新我有一些时间，我想我看到如何将上述内容集成到您的查询中。我真的没有SQL Fiddle的示例数据（无论如何你有很多表）。您可以在这里开始，这应该得到所有适当的访问以及访问日期范围内的每个日期（假设没有访问超过30天 - 相应地调整）：

WITH dr AS (
    SELECT LEVEL AS dd FROM dual
   CONNECT BY LEVEL <= 30 -- I'm assuming a max date range of 30; increase as you see fit
)
SELECT v.visit_id, v.start_date - 1 + dr.dd AS encounter_transaction_date
     , p.name_last, ett.enc_trans_type_name
  FROM visit v CROSS JOIN dr
 WHERE v.start_date - 1 + dr.dd < TRUNC(v.end_date) + 1
   AND v.institution_id = 1
   AND v.end_date IS NOT NULL
   AND v.voided_yn = 'N'
   AND v.care_setting_code = 'I'
   AND v.patient_team_id IN (16,17,18)
   AND v.start_date >= TRUNC(ADD_MONTHS(CURRENT_DATE, -1), 'MONTH')
   AND v.end_date < TRUNC(CURRENT_DATE, 'MONTH');

然后我认为你的外连接应该是那里的左连接（至少，如果我理解正确，我可能不会：

WITH dr AS (
    SELECT LEVEL AS dd FROM dual
   CONNECT BY LEVEL <= 30 -- I'm assuming a max date range of 30; increase as you see fit
)
SELECT v.visit_id, v.start_date - 1 + dr.dd AS encounter_transaction_date
  FROM visit v CROSS JOIN dr
  LEFT JOIN encounter_transaction et
    ON v.visit_id = et.visit_id
   AND v.institution_id = et.institution_id
   AND TRUNC(v.start_date - 1 + dr.dd) = et.encounter_transaction_date
  LEFT JOIN encounter_transaction_type ETT
    ON et.encounter_type_id = ett.encounter_transaction_type_id
  LEFT JOIN local_provider lp
    ON et.ordering_provider_id = lp.local_provider_id
  LEFT JOIN person_identifier i
    ON i.identifier = lp.provider_number
   AND i.identifier_sys_id = lp.provider_number_sys_id
   AND i.identifier IN (
       '1234', --Smith
       '4321' --Jones ** you had an extra comma here!
)
  LEFT JOIN person p
    ON p.person_id = i.person_id
 WHERE v.start_date - 1 + dr.dd < TRUNC(v.end_date) + 1
   AND v.institution_id = 1
   AND v.end_date IS NOT NULL
   AND v.voided_yn = 'N'
   AND v.care_setting_code = 'I'
   AND v.patient_team_id IN (16,17,18)
   AND v.start_date >= TRUNC(ADD_MONTHS(CURRENT_DATE, -1), 'MONTH')
   AND v.start_date < TRUNC(CURRENT_DATE, 'MONTH');

Oracle SQL循环到日期范围

1 个答案: