我想使用php mysql将用户兴趣存储在数据库中。输出在JSON中以树状结构提供,我使用print_r()打印:
Facebook/GraphUser Object
(
[backingData:protected] => Array
(
[data] => Array
(
[0] => stdClass Object
(
[category]=> Tours/sightseeing
[category_list] => Array
(
[0] => stdClass Object
(
[id] => 209888929023118
[name] => Landmark
)
[1] => stdClass Object
......
我的代码:
$user_interest = (new FacebookRequest($session, 'GET', '/me/interests')) ->execute()->getGraphObject(GraphUser::className());
为了将数据添加到数据库中,我发现了以下代码,但它不起作用:
for($i = 0; $i < sizeof($user_interest[data]); $i++)
{
$name = $user_interest[data][$i]['name'];
$category = $user_interest[data][$i]['category'];
$categoryId = $user_interest[data][$i]['id'];
//$created_time = $user_interest[data][$i]['created_time'];
$strsql = "INSERT INTO interests(categoryId,category,name)
VALUES($categoryId,$category,$name)";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
}
else {
echo "Error: " . $sql . "<br>" . $conn->error; }
请帮助我真的被困在这里......
答案 0 :(得分:0)
解决了它。这是我用过的东西
$books = (new FacebookRequest($session, 'GET', '/me/books'))
->execute()->getGraphObject()->asArray();
$booksarray=array();
for($i=0;$i<10;$i++){
$array = get_object_vars( $books['data'][$i]);
$booksarray[]=$array['name'];
}
然后我将数组存储在db:
中 function interests($booksarray, $fbid){
$query = "INSERT INTO Books (uid,book1,book2,book3,book4,book5,book6,book7,book8,book9,book10)
VALUES ('$fbid','$booksarray[0]','$booksarray[1]','$booksarray[2]','$booksarray[3]','$booksarray[4]','$booksarray[5]','$booksarray[6]','$booksarray[7]','$booksarray[8]','$booksarray[9]')";
mysql_query($query);
}
对此的任何改进都将受到赞赏。感谢