Question

我在boost::interprocess Containers of containers NOT in shared memory和How to I create a boost interprocess vector of interprocess containers中有类似的问题，但这次我喜欢使用我的类，它也使用scoped_allocator，也在堆和共享内存上。

我的first question的解决方案是使用具有分配器类型的模板类
在我的second previous question中，结果发现在共享内存中使用scoped_allocator和容器容器可以让生活更轻松。

现在我想拥有两者，这可能吗？附上一个工作scoped_allocator的例子，但我不知道如何在这种情况下模板化该类的分配器？

提前致谢： - ）

马库斯

#include <boost/interprocess/managed_shared_memory.hpp>
#include <boost/container/scoped_allocator.hpp>
#include <boost/interprocess/allocators/allocator.hpp>
#include <boost/interprocess/containers/vector.hpp>
#include <boost/algorithm/string.hpp>

namespace bi = boost::interprocess;
namespace bc = boost::container;

typedef bi::managed_shared_memory::segment_manager                         segment_manager_t;
typedef bc::scoped_allocator_adaptor<bi::allocator<void, segment_manager_t> >  void_allocator;

class CheckList {
typedef void_allocator::rebind<double>::other       double_allocator;
typedef bc::vector<double, double_allocator>         double_vector;
public:
    double_vector values;

    typedef void_allocator allocator_type;

    //Since void_allocator is convertible to any other allocator<T>, we can simplify
    //the initialization taking just one allocator for all inner containers.
    CheckList ( const allocator_type &void_alloc )
        :  values ( void_alloc ) {}

    CheckList ( CheckList const& other, const allocator_type &void_alloc )
        :  values ( other.values, void_alloc ) {}

    friend std::ostream &operator << ( std::ostream &os, const CheckList &o ) {
        for ( size_t i = 0; i < o.values.size(); i++ )  os << (i>0?", ":"") << o.values[i];
        return os;
    }
};

class Lists {
typedef void_allocator::rebind<CheckList>::other      checklist_allocator;
typedef bc::vector<CheckList, checklist_allocator>    checklist_vector;

public:
    Lists ( const void_allocator &void_alloc )
        : checklists ( void_alloc )
    {}
    checklist_vector checklists;

    friend std::ostream &operator << ( std::ostream &os, const Lists &o ) {
        for ( size_t i = 0; i < o.checklists.size(); i++ ) os << o.checklists[i]  << std::endl;
        return os;
    }
};


int main ( int argc, char **argv ) {


    if ( argc > 1 && (boost::iequals ( "clear", argv[1] ) || boost::iequals ( "c", argv[1] ) ) ) {
        std::cout << "Remove shared memory" << std::endl;
        bi::shared_memory_object::remove ( "MySharedMemory" );
    }


    //Create shared memory
    bi::managed_shared_memory segment ( bi::open_or_create,"MySharedMemory", 16*1024*1024 );

    //An allocator convertible to any allocator<T, segment_manager_t> type
    void_allocator alloc_inst ( segment.get_segment_manager() );

    Lists *lists = segment.find_or_construct<Lists> ( "Lists" ) ( alloc_inst );
    if ( lists->checklists.size() != 10 ) {
        std::cout << "Create Data" << std::endl;
        lists->checklists.resize ( 10 );
        for ( size_t i = 0; i < lists->checklists.size(); i++ ) {
            lists->checklists[i].values.resize ( i+1 );
            for ( size_t j = 0; j < lists->checklists[i].values.size(); j++ ) {
                lists->checklists[i].values[j] = j;
            }
        }
    } else {
        std::cout << "Data Exists" << std::endl;
    }
    std::cout << *lists << std::endl;
}

Answer 1

好。我不确定挑战是什么，除了......是的，让我们让分配器成为模板参数，然后定义

namespace Shared {
    typedef bi::managed_shared_memory::segment_manager                             segment_manager_t;
    typedef bc::scoped_allocator_adaptor<bi::allocator<void, segment_manager_t> >  void_allocator;
    using Lists = common::Lists<void_allocator>;
}

namespace Heap {
    typedef std::allocator<void> void_allocator;
    using Lists = common::Lists<void_allocator>;
}

所以，我继续前进并实际上转换了构造函数：

<强> Live On Coliru

namespace common {
    template <typename Alloc>
    class CheckList {
        typedef typename Alloc::template rebind<double>::other double_allocator;
        typedef bc::vector<double, double_allocator> double_vector;

    public:
        double_vector values;

        typedef Alloc allocator_type;
        CheckList(const allocator_type& void_alloc = allocator_type()) : values(void_alloc) {}

        template <typename Alloc2>
        CheckList(CheckList<Alloc2> const& other, const allocator_type& void_alloc = allocator_type())
        : values(void_alloc)
        {
            for(auto& v : other.values) values.emplace_back(v);
        }

        friend std::ostream& operator<<(std::ostream& os, const CheckList& o) {
            for (size_t i = 0; i < o.values.size(); i++)
                os << (i?", ":"") << o.values[i];
            return os;
        }
    };

    template <typename Alloc>
    class Lists {
        typedef typename Alloc::template rebind<CheckList<Alloc> >::other checklist_allocator;

    public:
        typedef Alloc allocator_type;
        typedef bc::vector<CheckList<Alloc>, checklist_allocator> checklist_vector;

        template <typename Alloc2>
        Lists& operator=(Lists<Alloc2> const& other) {
            for(auto& cl : other.checklists) checklists.emplace_back(cl);
            return *this;
        }

        Lists(const Alloc& void_alloc = allocator_type()) : checklists(void_alloc) {}
        checklist_vector checklists;

        friend std::ostream& operator<<(std::ostream& os, const Lists& o) {
            for (size_t i = 0; i < o.checklists.size(); i++)
                os << o.checklists[i] << '\n';
            return os;
        }
    };
}

这意味着您现在可以拥有一个返回基于堆的集合的函数，并将其分配给相同的共享内存版本：

Heap::Lists generate_local() {
    Heap::Lists lists;
    Heap::Lists::checklist_vector::value_type v;

    for (int i=0; i<10; ++i) {
        v.values.emplace_back(i+1);
        lists.checklists.push_back(v);
    }

    return lists;
}

// later:

    Lists& lists = *segment.find_or_construct<Lists>("Lists")(alloc_inst);

    if (lists.checklists.size() != 10) {
        std::cout << "Create Data" << std::endl;
        auto x = generate_local();
        lists = std::move(x);
    }

boost :: interprocess scoped_allocator和不在共享内存中的容器容器

1 个答案: