我有6个表,我想要访问数据。并将其显示在一个表中。表是
T1
name|date |item |remarks|size
abc |18-2-2015|25mm series|done |25
xyz |17-2-2015|25mm series|done |30
T2
name|date |item |remarks|size
abc |14-2-2015|30mm series|done |25
xyz |16-2-2015|30mm series|done |30
T3
name|date |item |remarks|size
abc |11-2-2015|35mm series|done |25
xyz |13-2-2015|35mm series|done |30
T4
name|date |item |remarks|size
abc |10-2-2015|40mm series|done |25
abc |15-2-2015|40mm series|done |30
xyz |16-2-2015|40mm series|done |30
T5
name|date |item |remarks|size
abc |6-2-2015 |45mm series|done |25
abc |5-2-2015 |45mm series|done |30
xyz |6-2-2015 |45mm series|done |30
T6
name|date |item |remarks|size
abc |6-2-2015 |50mm series|done |25
abc |5-2-2015 |50mm series|done |30
xyz |6-2-2015 |50mm series|done |30
这些是包含数据的表格,我想要结果,如果我给出的名称是abc我想要显示与该名称相关的所有6个表格数据。输出结果
输出
name|date |item |remarks
abc |6-2-2015 |50mm series|done
abc |5-2-2015 |50mm series|done
abc |6-2-2015 |50mm series|done
abc |5-2-2015 |50mm series|done
abc |6-2-2015 |45mm series|done
abc |5-2-2015 |45mm series|done
abc |10-2-2015|40mm series|done
abc |15-2-2015|40mm series|done
abc |11-2-2015|35mm series|done
abc |14-2-2015|30mm series|done
abc |18-2-2015|25mm series|done
我试过这个查询但是得到了空
select t1.Name,t1.Date,t1.Item,t1.Remarks
from t1 p1
inner join t2 on t1.Name=t2.Name
inner join t3 on t1.Name=t3.Name
inner join t4 on t1.Name=p4.Name
inner join t4 on t1.Name=p5.Name
inner join t5 on t1.Name=p6.Name
inner join t6 on t1.Name=p2.Name
where t1.CheckListName='abc'
答案 0 :(得分:0)
联盟将从所有表中选择与返回相同行的贫困行。尝试,
select Name, Date, Item, Remarks
from t1 where name = 'abc'
UNION
select Name, Date, Item, Remarks
from t2 where name = 'abc'
UNION
select Name, Date, Item, Remarks
from t3 where name = 'abc'
UNION
select Name, Date, Item, Remarks
from t4 where name = 'abc'
UNION
select Name, Date, Item, Remarks
from t5 where name = 'abc'
UNION
select Name, Date, Item, Remarks
from t6 where name = 'abc'
答案 1 :(得分:0)
试试这个
SELECT * FROM (
SELECT * FROM t1
UNION ALL
SELECT * FROM t2
UNION ALL
SELECT * FROM t3
UNION ALL
SELECT * FROM t4
UNION ALL
SELECT * FROM t5
UNION ALL
SELECT * FROM t6
) AS Total
WHERE NAME = 'abc'
我认为你不应该有任何错误。