如何将XStream引用传递给camel进行编组

Question

来自http://camel.apache.org/xstream.html

的示例代码

  

如果您想配置Camel用于消息转换的XStream实例，您只需在DSL级别上传递对该实例的引用。

XStream xStream = new XStream();
xStream.aliasField("money", PurchaseOrder.class, "cash");
// new Added setModel option since Camel 2.14
xStream.setModel("NO_REFERENCES");
...

from("direct:marshal").
  marshal(new XStreamDataFormat(xStream)).
  to("mock:marshaled");

但是这段代码是错误的，因为org.apache.camel.model.dataformat.XStreamDataFormat构造函数只接受String。如何在camel中配置自定义com.thoughtworks.xstream.XStream？

我不想使用XML，我的应用程序使用的是Spring。

Answer 1

如果你想快速完成它，而不是通过“marshal”，你可以重定向到一个编组“bean”，它将以你需要的方式进行游戏。

from(...).bean('marshallingBean').to(...)

完整代码

@Autowired
FooDeserializer fooDeserializer;

@Bean
public RouteBuilder route() {
    return new RouteBuilder() {
        public void configure() {
            from("direct:marshal")
                    .bean(fooDeserializer)
                    .to("mock:marshaled");
        }
    };
}

FooDeserializer.java

@Component
public class FooDeserializer {

    private final XStream xStream;

    public FooDeserializer() {
        xStream = new XStream();
        xStream.aliasField("money", PurchaseOrder.class, "cash");
    }

    public Foo xmlToFoo(String xml) {
        return (Foo) xStream.fromXML(xml);
    }

}

Answer 2

确保使用

import org.apache.camel.dataformat.xstream.XStreamDataFormat;

而不是

import org.apache.camel.model.dataformat.XStreamDataFormat;

为班级

new XStreamDataFormat(xStream)

Answer 3

我的解决方案。

final XStream xStream = new XStream();
xStream.aliasField("money", PurchaseOrder.class, "cash");

from("direct:marshal")
        .process(new Processor() {
            @Override
            public void process(Exchange exchange) {
                String xmlConverted = xStream.toXML(exchange.getIn().getBody());
                exchange.getIn().setBody(xmlConverted);
            }
        }).to("mock:marshaled");