Question

这是我的情景：我有一个Rest服务，它在查询部分中有一个字符串参数，它将被反序列化为包含byte []的复杂对象：

        [OperationContract]
        [WebInvoke(Method = "PUT",
            ResponseFormat = WebMessageFormat.Json,
            RequestFormat = WebMessageFormat.Json, 
            BodyStyle = WebMessageBodyStyle.Wrapped,
            UriTemplate = "json?doc={doc}")]
        string UploadDocument(string doc);

这是我的UploadDocument继承：

public string UploadDocument(string doc) 
{
    if(string.IsNullOrEmpty(doc))
        return "ko";
    JavaScriptSerializer jscript = new JavaScriptSerializer();
    Document inputDocument = jscript.Deserialize<Document>(doc);
    return "ok";
}

我需要从客户端调用它来读取文件的内容并将其放在参数中：

JavaScriptSerializer jscript = new JavaScriptSerializer();
            Document newComp = jscript.Deserialize<Document>(test);
            newComp.Content = File.ReadAllBytes(@"D:\Test\PdfParse\test.pdf");
            newComp.filename = "test.pdf";

            test = jscript.Serialize(newComp);
            ASCIIEncoding encoder = new ASCIIEncoding();
            byte[] data = encoder.GetBytes(test);
            WebRequest request = WebRequest.Create("http://localhost/DocumentUpload/DocumentUpload.svc/json?doc=");
            request.Method = "POST";
            request.ContentType = "application/json";
            request.ContentLength = data.Length;

            Stream requestStream = request.GetRequestStream();
            requestStream.Write(data, 0, data.Length);
            requestStream.Close();
            WebResponse wr = request.GetResponse();

            using (StreamReader sw = new StreamReader(wr.GetResponseStream()))
            {
                test = (sw.ReadToEnd());

            }

问题如果我在WebRequest.Create中添加“test”内容，则url太长，但将其写入requestStream rest服务返回给我“doc”始终为空。我可以通过哪种方式传递参数？

Answer 1

您可以在方法中使用multipart_form_data媒体类型。在这种情况下，您可以直接将流传递给您的代码。

我认为此链接可以帮助您： http://www.briangrinstead.com/blog/multipart-form-post-in-c

祝你好运

使用查询部分发送长uri到休息服务

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