Question

$ mysqli = new mysqli（“localhost”，“root”，“”，“test”）; $ mysqli-＆gt; query（'PREPARE mid FROM“SELECT name FROM test_user WHERE id =？”'）; //工作代码开始 // $ res = $ mysqli-＆gt; query（'PREPARE mid FROM“SELECT name FROM test_user”'）; // $ res = $ mysqli-＆gt; query（'EXECUTE mid;'）或die（mysqli_error（$ mysqli））; //工作代码结束.. $ res = $ mysqli-＆gt;查询（'EXECUTE mid 1;'）或死（mysqli_error（$ mysqli））;

while($resu = $res->fetch_object()) {
    echo '<br>' .$resu->name;
}

错误：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1

我的php版本是PHP Version 5.3.0和mysql

mysqlnd 5.0.5-dev - 081106 - $Revision: 1.3.2.27 $

我使用where clause

得到了正确的结果

Answer 1

将SELECT函数用于SELECT查询：

http://php.net/manual/en/mysqli.prepare.php

/* create a prepared statement */
if ($stmt = $mysqli->prepare("SELECT District FROM City WHERE Name=?")) {

    /* bind parameters for markers */
    $stmt->bind_param("s", $city);

    /* execute query */
    $stmt->execute();

    /* bind result variables */
    $stmt->bind_result($district);

    /* fetch value */
    $stmt->fetch();

    /* close statement */
    $stmt->close();
}

Answer 2

http://dev.mysql.com/doc/refman/5.1/en/execute.html

您需要在EXECUTE语句中使用using子句。所以你可以这样做：

$mysqli = new mysqli("localhost", "root", "", "test");
$mysqli->query('PREPARE mid FROM "SELECT name FROM test_user WHERE id = ?"');
$mysqli->query('SET @var1 = 1;');
$res = $mysqli->query( 'EXECUTE mid USING @var1;') or die(mysqli_error($mysqli));

mysqli准备语句错误？

2 个答案: