我正在运行以下代码,以获取从3个不同.txt文件中获取数据的程序。当我尝试按列发布值时,似乎无法控制我的数据发布的行。
#include <stdio.h>
#include <string.h>
int
main (void)
{
FILE *data_File;
FILE *lake_File;
FILE *beach_File;
char fileName[10], lake_Table[15],beach_Table[15]; /*.txt file names */
int lake_data=0,lake_x=0, beach_x=0, nr_tests=0; /* variables for the data within the file july08.txt */
int province_data=0,prv_x=0; /* variables for the file Lake Table.txt */
int beach_data=0,bch_x=0; /* variables for the file Beach Table.txt*/
char province[30] = ""; /*variable for the file Lake Table.txt*/
char beach[20]=""; /*variable for the file Beach Table.txt*/
int j;
double status, ecoli_lvl;
printf ("Which month would you like a summary of? \nType month followed by date (i.e: july05): ");
gets(fileName);
/*Opening the files needed for the program*/
data_File = fopen (fileName, "r");
lake_File = fopen ("Lake Table.txt", "r");
beach_File = fopen ("Beach Table.txt", "r");
/*These are my columns*/
printf ("\n Lake Beach Average E-Coli Level Recommendation\n");
/* july08.txt file*/
fscanf (data_File, "%d", &lake_x);
fscanf (data_File, "%d", &beach_x);
lake_data = fscanf (data_File, "%d", &nr_tests);
/* Lake Table.txt file*/
province_data = fscanf (lake_File, "%d", &prv_x);
fgets (province,30,lake_File);
/* Beach Table.txt file*/
beach_data = fscanf (beach_File, "%d", &bch_x);
fgets (beach,20,beach_File);
status = (double) 0;
while (province_data > 0)
{
if (lake_x == prv_x)
{
province_data = 0;
while (beach_data > 0)
{
if (beach_x == bch_x)
{
beach_data = 0;
}
else
{
beach_data = fscanf (beach_File, "%d", &bch_x);
fgets (beach,30,beach_File);
}
}
}
else
{
province_data = fscanf (lake_File, "%d", &prv_x);
fgets (province,30,lake_File);
}
这是我的问题发生的地方。我希望下面两个变量打印在各自列下的同一行上。我已经编辑了我需要的空间,但由于某种原因,第二个变量是海滩&#39;在第二行发布。注意:通过&#39;海滩的条件声明的数据&#39;变量位于第二个文件的第二行。这就是为什么它被贴在第二排?如何控制我的数据发布到哪一行?
printf ("%s %s", province, beach);
}
更新声明的条件(使用strlen方法)
while (lake_data != EOF)
{
while (province_data > 0)
{
if (lake_x == prv_x)
{
province_data = 0;
while (beach_data > 0)
{
if (beach_x == bch_x)
{
beach_data = 0;
}
else
{
beach_data = fscanf (beach_File, "%d", &bch_x);
fgets (beach,30,beach_File);
}
}
}
else
{
province_data = fscanf (lake_File, "%d", &prv_x);
fgets (province,30,lake_File);
}
if (province[strlen(province)-1] =='\n')
{
province[strlen(province)-1] ='\0';
beach[strlen(beach)-1] ='\0';
}
/*code was right here*/
}
for (j=1; j<=nr_tests; ++j)
{
fscanf (data_File, "%lf", &ecoli_lvl);
status = status + ecoli_lvl;
}
printf ("%s %s %.2f", province, beach, status);
/* printf (" %.2f", status); */
/* Lake Table.txt file*/
province_data = fscanf (lake_File, "%d", &prv_x);
fgets (province,30,lake_File);
/* Beach Table.txt file*/
beach_data = fscanf (beach_File, "%d", &bch_x);
fgets (beach,20,beach_File);
fscanf (data_File, "\n%d", &lake_x);
fscanf (data_File, "%d", &beach_x);
lake_data = fscanf (data_File, "\n%d", &nr_tests);
printf ("\n");
status = (double) 0;
}
fclose (data_File);
return (0);
} 这是我的输出:我在&#34;&#34;中使用了tab命令。试图调整我的文字,但你可以看到它不是很有效。我怎样才能解决这个问题?
答案 0 :(得分:4)
您正在从fgets
获取输入,它获取包含换行符的行,
之后,它将空值。
当您打印放置在该字符串中的province
换行符时。所以第二个变量打印在下一行。
if ( province[strlen(province)-1] == '\n' )
province[strlen(province)-1] = '\0';
测试,因为它在读取文件的最后一行时可能有EOF
个字符。
来自fgets
的手册页,
在EOF或换行符后停止阅读。如果读取换行符,则将其存储到 缓冲。终止空字节(&#39; \ 0&#39;)存储在缓冲区中的最后一个字符之后。
请参阅此link了解strlen()
。它是一个简单的函数,用于获取放置在给定字符串中的总字符数,包括空字符。它只适用于字符串。
像这样你必须使用。
if (province[strlen(province)-1] == '\n')
{
province[strlen(province)-1] = '\0';
beach[strlen(beach)-1] = '\0';
}
printf ("%s %s", province, beach);
}
格式:
打印scanf
时,您可以使用-
。用于打印正确的空间。
printf("test:%-10s\n","Testing");
它将给出尾随空格。在这种情况下,测试是七个字符,因此有三个尾随空格。