提取字符串组件以在函数,模式匹配器中存储为哈希映射关键字?

时间:2015-02-19 03:19:57

标签: java regex pattern-matching

我将数据存储在路径中的文件中,例如:

/home/yamada/data/train/atheism/file_name.txt

我使用此数据填充哈希映射,存储数据的来源及其内容,如下所示。

/home/yamada/data/test/sports/t.s_1.txt, [0, 0, 1, 1, 0, 0, 0, 0, 0, 1, 0, 1, 1, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0]
/home/yamada/data/test/politics/t.p_0.txt, [0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0]
/home/yamada/data/test/atheism/t.a_0.txt, [0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
/home/yamada/data/test/science/t.s_0.txt, [1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 2, 0, 0, 0, 1, 1, 1, 1, 0, 1, 0]

但是,我只希望将路径存储到目录点,而不是特定文件,如下所示:

/home/yamada/data/train/atheism

以下正则表达式命令能够根据regex101.com提取我感兴趣的组件:

(home\/yamada\/data\/train\/atheism)

我如何使用java模式匹配器来确保只将前面提到的字符串(包括目录的路径,而不是文件名)保存到哈希映射中?

模式匹配器是此操作的最佳选择吗?

下面是填充哈希映射的方法。

public static void perceptron_data_struc_generateur(Set<String> GLOBO_DICT, 
                                                        Map<File, ArrayList<String> > fileDict,
                                                        Map<File, int[] > perceptron_input)
    {
        //create a new entry in the array list 'perceptron_input'
        //with the key as the file name from fileDict
            //create a new array which is the length of GLOBO_DICT
            //iterate through the indicies of GLOBO_DICT
                //for all words in globo dict, if that word appears in fileDict,
                //increment the perceptron_input index that corresponds to that
                //word in GLOBO_DICT by the number of times that word appears in fileDict

        //so i can get the index later
        List<String> GLOBO_DICT_list = new ArrayList<>(GLOBO_DICT);

        for (Map.Entry<File, ArrayList<String>> entry : fileDict.entrySet()) 
        {
            int[] cross_czech = new int[GLOBO_DICT_list.size()];
            //initialize to zero
            Arrays.fill(cross_czech, 0);

            for (String s : GLOBO_DICT_list)
            {

                for(String st : entry.getValue()) 
                {
                    if( st.equals(s) )
                    {
                        cross_czech[ GLOBO_DICT_list.indexOf( s ) ] = cross_czech[ GLOBO_DICT_list.indexOf( s ) ] +1;
                    }
                }
            }
            perceptron_input.put( entry.getKey() , cross_czech);    
        }
    }

2 个答案:

答案 0 :(得分:1)

比这简单得多:

String dir = filename.replaceAll("/[^/]*$", "");

答案 1 :(得分:0)

如果我正确理解您的问题,您只想找到以/结尾的部分(文件名不会有)。在那种情况下

(\w+/)+

should do the trick(顺便说一下,我们不会在Java的正则表达式中转义/


但是,如果您的数据始终采用path/to/file格式而您只想提取path/to,那么您不需要正则表达式,您可以使用File类及其getParent方法,例如< / p>

String data = new File("/home/yamada/data/train/atheism/file_name.txt").getParent();
System.out.println(data);

这将返回\home\yamada\data\train\atheism,因此您将/而不是\,但如果您想在Java中使用此数据,这不应该是一个问题({{1} }接受两个分隔符。)