在与元组的邻居列表匹配的元组列表中弹出元组

Question

一个元组列表如下：

[(5,), (4,), (7,)]

第二个是：

[(7,'James',6,1), (3,'Don',4,3), (2,'Poppy',5,1), (4,'Dom',6,4)]

如果要在第一个列表中找到第一个元素，我希望在第二个列表中弹出元组。即，返回第二个列表如下：

[(3,'Don',4,3), (2,'Poppy',5,1)]

Answer 1

In [32]: list1 = [(5,), (4,), (7,)]

In [33]: list2 = [(7,'James',6,1), (3,'Don',4,3), (2,'Poppy',5,1), (4,'Dom',6,4)]

In [34]: [ x for x in list2 if x[:1] not in list1]
Out[34]: [(3, 'Don', 4, 3), (2, 'Poppy', 5, 1)]

Answer 2

>>> x = [(5,), (4,), (7,)]
>>> y = [(7,'James',6,1), (3,'Don',4,3), (2,'Poppy',5,1), (4,'Dom',6,4)]
>>> set_x = set(x)
>>> y[:] = [t for t in y if t[:1] not in set_x]
>>> y
[(3, 'Don', 4, 3), (2, 'Poppy', 5, 1)]