Question

我需要帮助修改我编写的broadcastReceiver，以便它只显示我可以指定的数字的传入短信。现在，以下代码显示所有收到的短信，如果应用程序仅显示1个特定号码的短信，那将是很好的。任何人都可以提供有关如何实现这一目标的任何细节吗？

代码如下：

public class IncomingSms extends BroadcastReceiver {

   final SmsManager sms = SmsManager.getDefault();

   public void onReceive(Context context, Intent intent) {

      // Retrieves a map of extended data from the intent.
      final Bundle bundle = intent.getExtras();

      try {

          if (bundle != null) {

              final Object[] pdusObj = (Object[]) bundle.get("pdus");

              for (int i = 0; i < pdusObj.length; i++) {

                  SmsMessage currentMessage = SmsMessage.createFromPdu((byte[]) pdusObj[i]);
                  String phoneNumber = currentMessage.getDisplayOriginatingAddress();

                  String senderNum = phoneNumber;
                  String message = currentMessage.getDisplayMessageBody();

                  Log.i("SmsReceiver", "senderNum: "+ senderNum + "; message: " + message);


                 // Show Alert
                  int duration = Toast.LENGTH_LONG;
                  Toast toast = Toast.makeText(context, 
                             "senderNum: "+ senderNum + ", message: " + message, duration);
                  toast.show();

              } // end for loop
            } // bundle is null

    } catch (Exception e) {
        Log.e("SmsReceiver", "Exception smsReceiver" +e);

    }
  }    
}

非常感谢帮助。

Answer 1

只要放一个：）

public class IncomingSms extends BroadcastReceiver {
   private static final String MY_PHONE_NUMBER = "your number here";
   final SmsManager sms = SmsManager.getDefault();

   public void onReceive(Context context, Intent intent) {

      // Retrieves a map of extended data from the intent.
      final Bundle bundle = intent.getExtras();

      try {

          if (bundle != null) {

              final Object[] pdusObj = (Object[]) bundle.get("pdus");

              for (int i = 0; i < pdusObj.length; i++) {
                  SmsMessage currentMessage = SmsMessage.createFromPdu((byte[]) pdusObj[i]);
                  String phoneNumber = currentMessage.getDisplayOriginatingAddress();

                  if(!MY_PHONE_NUMBER.equals(phoneNumber)) {
                      return;
                  }

                  ...

如何设置BroadcastReceiver仅显示从特定号码收到的短信？

1 个答案: