问题在mySQL中创建select

Question

我已经得到了它并且它无法正常工作（SQL语法错误）：

SELECT database_percent, national_percent, (database_percent/national_percent) AS calculated_index INT(3) FROM full_data_complete

如果我取出INT(3)部分，它运行正常。

我希望创建一个以INT(3)作为格式的选择。我需要做些什么？

Answer 1

据我了解，您可以使用以下方法之一：

SELECT database_percent, national_percent, format(database_percent/national_percent, 0) AS calculated_index FROM full_data_complete

或

SELECT database_percent, national_percent, cast(database_percent/national_percent as signed) AS calculated_index FROM full_data_complete

或

SELECT database_percent, national_percent, round(database_percent/national_percent, 0) AS calculated_index FROM full_data_complete

我希望这会有所帮助。